Timeline for Singular quadratic space
Current License: CC BY-SA 3.0
2 events
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| Jul 2, 2012 at 15:43 | comment | added | Paul Reynolds | I'm not sure I've understood you correctly, but it seems to me that over $\mathbb{R}$ the result fails if and only if the signature of the bilinear form on $V/V^{\perp}$ is indefinite. Take an element of $V^{\perp}$ and send it to a null element of $V$ not in $V^{\perp}$ - this of course cannot extend. Over $\mathbb{C}$ there are always null vectors... this may not be what you mean. | |
| Jul 2, 2012 at 14:33 | history | asked | Wanderer | CC BY-SA 3.0 |