Timeline for Fundamental problems whose solution seems completely out of reach
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Sep 9, 2020 at 3:06 | comment | added | Gerry Myerson | The Erdos conjecture is that $A$ contains arithmetic progressions of arbitrary length. That $A$ contains a 3-term AP (or infinitely many 3-term APs) is the simplest special case. And this special case is what's proved at the arxiv reference, without resolving the general case. | |
Sep 5, 2020 at 3:38 | comment | added | Antoine Labelle | This is now solved! Seems like this wasn't that much out of reach. arxiv.org/abs/2007.03528 | |
May 8, 2018 at 13:38 | comment | added | C.S. | @Kevin: What doing mean by saying $A$ contains a 3-term arithmetic progession? | |
Nov 7, 2013 at 4:31 | comment | added | Suvrit | wow, in my ignorance, I find it hard to believe that this question is within the "completely out of reach" category! really awesome question though! | |
Jul 1, 2012 at 15:12 | history | answered | Kevin O'Bryant | CC BY-SA 3.0 |