Timeline for Homology of homotopy fixed point spectra
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 4, 2012 at 19:52 | answer | added | Peter May | timeline score: 4 | |
| Jul 1, 2012 at 12:53 | vote | accept | Akhil Mathew | ||
| Jul 1, 2012 at 11:18 | answer | added | Tom Goodwillie | timeline score: 10 | |
| Jul 1, 2012 at 5:40 | comment | added | Tyler Lawson | @Akhil: The truncation is a right adjoint, but only if the target is a different category (connective spectra). In that category, the homotopy fixed point object of $ku$ is indeed $ko$. | |
| Jul 1, 2012 at 3:25 | answer | added | Craig Westerland | timeline score: 8 | |
| Jul 1, 2012 at 2:36 | comment | added | Akhil Mathew | I thought that taking homotopy fixed points would commute with truncation $\tau_{\geq 0}$ (which is a right adjoint, right?). Is there something that goes wrong here? | |
| Jul 1, 2012 at 2:34 | history | edited | Akhil Mathew | CC BY-SA 3.0 |
added 84 characters in body
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| Jun 30, 2012 at 20:21 | answer | added | Peter May | timeline score: 6 | |
| Jun 30, 2012 at 20:17 | comment | added | André Henriques | I think that, while $KU^{\mathbb Z/2}=KO$, it is NOT true that $ku^{\mathbb Z/2}=ko$. If you run the homotopy fixed point spectral sequence, it's ptretty obvious that you don't get $\pi_*(ko)$ from $H^*(\mathbb Z/2;\pi_*(ku))$. | |
| Jun 30, 2012 at 17:36 | history | asked | Akhil Mathew | CC BY-SA 3.0 |