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Dec 8, 2015 at 11:13 comment added Thomas Benjamin JDH: Since Lindenbaum algebras define $\forall$ as infinite conjunctions and $\exists$ as infinite disjunctions, what happens to the undecidable theory $T$ in question when such infinite conjunctions and disjunctions are removed and only finite conjunctions and disjunctions remain (bounded quantification)? If I understand correctly, all terms in the conjunctions and disjunctions are variable-free. Does this make this fragment of $T$ 'contentual' ('finitary' in Hilbert's terminology) and is this fragment always decidable?
Jul 3, 2012 at 18:31 comment added Peter Smith My comment, on reflection, is the same as for Ali Enayat's lovely case. Here too we have an r.e. set of sentences, but not recursively decidable as presented, so not a recursively axiomatized theory in the (I hope non-deviant) sense I was using. No?
Jun 29, 2012 at 21:24 vote accept Peter Smith
Jun 30, 2012 at 22:37
Jun 29, 2012 at 17:07 history answered Joel David Hamkins CC BY-SA 3.0