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Jul 2, 2012 at 14:46 history edited David Ketcheson CC BY-SA 3.0
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Jul 2, 2012 at 10:18 history edited David Ketcheson CC BY-SA 3.0
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Jul 1, 2012 at 9:35 comment added David Ketcheson No, $x$ is the minimum over $a$ of the maximum over $\lambda$ of the modulus of $R(h\lambda)$, as stated. In any case, $a$ is a vector. Is it not clear as written?
Jun 30, 2012 at 21:06 comment added Brian Borchers Do you really want $x$ be to the value of $a$ that minimizes $\max_{\lambda \in \Lambda} | R(h\lambda) |$, or do you want $x$ to be the minimal objective value?
Jun 30, 2012 at 20:49 history edited David Ketcheson CC BY-SA 3.0
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Jun 29, 2012 at 13:02 history asked David Ketcheson CC BY-SA 3.0