Timeline for distance regular metric spaces
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 5, 2010 at 13:58 | vote | accept | Dima Fon-Der-Flaass | ||
| Jan 5, 2010 at 13:58 | |||||
| Dec 30, 2009 at 4:12 | comment | added | Anton Petrunin | You can not construct a geodesic space this way (i.e. all points can be joined by minimizing geodesic). AND our space is geodesic. But it should work if $p>0$ for non-degenerate triangles only... | |
| Dec 29, 2009 at 19:12 | comment | added | macbeth | This is a beautiful idea. I think a small modification is needed, since the set X you choose at present doesn't necessarily have complete regularity for triples where the triangle inequality is equality. But we can fix this, say, by asking also that X intersects each line in exactly 2 points -- i.e., that no three points in X are collinear. Then p(a, b, a-b) = p(a, a-b, b) = p(a-b, a, b) = 0. I'm not sure if in such a construction p can take nonzero values for the "equality" triples, though. | |
| Dec 29, 2009 at 18:49 | history | answered | fedja | CC BY-SA 2.5 |