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Jun 30, 2012 at 14:36 comment added Ali Enayat Joel, you are right, my concern is with the wording of David's answer.
Jun 28, 2012 at 9:32 comment added Joel David Hamkins But Ali, those two notions are deeply connected: every strictly $\Pi^0_n$ set $A$, for nonzero $n$, has infinitely many $k$ for which the assertion $k\in A$ is independent of your favorite theory, for otherwise the proof-search algorithm would show that $A$ is not actually $\Pi^0_n$.
Jun 28, 2012 at 1:30 comment added Ali Enayat David, how exactly does the set you describe provide "such a sentence"? It seems to me that your solution is conflating two meanings of the word "undecidable": one meaning applies to a set of integers, the other to a sentence.
Jun 23, 2012 at 17:21 vote accept Mirco A. Mannucci
Jun 23, 2012 at 13:36 history answered David Harris CC BY-SA 3.0