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Jun 23, 2012 at 0:48 vote accept Yulia Kuznetsova
Jun 23, 2012 at 0:48 comment added Yulia Kuznetsova Indeed, $G(X)=F(x)-(1-z)x$ is a morphism but one cannot get anything better...
Jun 22, 2012 at 18:35 history answered Dmitri Pavlov CC BY-SA 3.0