Timeline for Is it possible to classify the boundaries of a manifold?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Mar 2, 2014 at 9:20 | answer | added | Sam Nead | timeline score: 2 | |
| Mar 2, 2014 at 0:50 | history | edited | user9072 |
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| Jun 19, 2012 at 23:21 | comment | added | Lawrence D'Anna | lee: thanks! It looks like the other question is exactly the discussion I was looking for. | |
| Jun 19, 2012 at 22:25 | comment | added | Lawrence D'Anna | mark: oops. convex polyhedron. | |
| Jun 19, 2012 at 22:24 | history | edited | Lawrence D'Anna | CC BY-SA 3.0 |
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| Jun 19, 2012 at 21:39 | comment | added | Mark Grant | I think you will need to make your question more precise, or risk closure. For instance, you seem to be suggesting that every closed polyhedron is homeomorphic to a closed ball, which is patently false. | |
| Jun 19, 2012 at 21:38 | comment | added | Lee Mosher | You might want to peruse mathoverflow.net/questions/22441/… for some other answers. | |
| Jun 19, 2012 at 21:35 | comment | added | Lee Mosher | If a manifold can be compactified with a boundary, then the original manifold and its compactification are homotopy equivalent, and the fundamental group is finitely generated. So the infinite ladder surface, with nonfinitely generated fundamental group, is a counterexample. | |
| Jun 19, 2012 at 21:30 | history | asked | Lawrence D'Anna | CC BY-SA 3.0 |