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Jun 21, 2012 at 6:44 vote accept Ali Reza
Jun 20, 2012 at 16:16 answer added Joseph Van Name timeline score: 1
Jun 20, 2012 at 13:30 answer added Pietro Majer timeline score: 2
Jun 19, 2012 at 23:48 answer added François G. Dorais timeline score: 5
Jun 19, 2012 at 23:08 answer added user24527 timeline score: 0
Jun 19, 2012 at 22:24 comment added Andreas Blass Gerald Edgar's example easily generalizes to show that the zero-set of any continuous real-valued function on $X$ would have to be open. Thus, all continuous functions from $X$ to $\mathbb R$ have to be locally constant.
Jun 19, 2012 at 19:33 history edited Ali Reza CC BY-SA 3.0
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Jun 19, 2012 at 19:20 comment added Ali Reza Thanks Dear Edgar. But I think I forgot to pose the important part of my Question. For this I must apologize from members of "MO". I will fixe it.
Jun 19, 2012 at 19:12 comment added Gerald Edgar Inn general, no. Say $X$ is the real line, $\epsilon_x=x$ for $x \ne 0$ and $\epsilon_0=1$.
Jun 19, 2012 at 18:45 history asked Ali Reza CC BY-SA 3.0