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Timeline for Colimits of schemes

Current License: CC BY-SA 2.5

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Dec 10, 2010 at 4:17 comment added Emerton Dear Martin, My reconstruction effort has failed, at least for the moment, and so I have added a further edit, scaling back the claim of the previous one.
Dec 10, 2010 at 4:17 history edited Emerton CC BY-SA 2.5
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May 9, 2010 at 4:20 comment added Emerton Dear Martin, I will try to reconstruct the proof, and then post it.
May 8, 2010 at 19:42 comment added Martin Brandenburg I still have not understood the claim in the EDIT if $I$ is not maximal.
Dec 29, 2009 at 10:42 comment added Martin Brandenburg in the general case, let $U \subseteq X$ be an open affine. since the transition maps $Spec A/I^n \to Spec A/i^{n+1}$ are homeomorphisms, the images of the $f_n$ are all equal. consider the preimage of $U$ in $Spec A/I$. let $f \in A$ such $D(\overline{f})$ is a basic open subset of this preimage. then all the $f_n$ restrict to compatible $Spec A_f / (I_f)^n \to U$. the affine case yields $Spec \hat{A_f} \to U$. now we want to glue these morphisms to $Spec \hat{A} \to X$. so it would be nice that $Spec \hat{A_f}$ is an open cover of $Spec \hat{A}$, but this seems to be unlikely ...
Dec 29, 2009 at 10:41 comment added Martin Brandenburg in general, the colimit of local affine schemes and local transition maps exists and is a local affine scheme. this is because you can describe morphisms on local schemes via points and local homomorphisms on the stalks. in particular, the colimit of the $Spec A/I^n$ is $Spec \hat{A}$, when $I$ is a maximal ideal. I try to prove the general case: if $f_n : Spec A/I^n \to X$ are compatible morphisms, we want to glue them to $Spec \hat{A} \to X$. if $X$ is affine, this is trivial.
Dec 29, 2009 at 8:32 history edited Emerton CC BY-SA 2.5
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Dec 29, 2009 at 3:56 history answered Emerton CC BY-SA 2.5