1
$\begingroup$

Let $A$ be a subcomplex of a CW complex $X$, let $Y$ be a CW complex, and let $f: A \to Y$ be a cellular map. What is the relationship between $H_*(X, A)$ and $H_*(Y \cup_f X, Y)$? Is there a similar relationship between $\pi_*(X, A)$ and $\pi_*(Y \cup_f X, Y)$?

Apologies in advance if this question is sort of remedial...

$\endgroup$
3
  • $\begingroup$ For homology, they're isomorphic. For homotopy, they're isomorphic through a range depending on the connectivity of these spaces. For details, look for the word "excision" in any standard algebraic topology textbook, e.g. Hatcher. $\endgroup$ Sep 1, 2015 at 14:24
  • $\begingroup$ Could I have a counterexample to isomorphism in the case for homotopy? $\endgroup$
    – User
    Sep 1, 2015 at 14:34
  • $\begingroup$ Start with the wedge of a circle and a sphere and then fill in the disk. $\endgroup$ Sep 1, 2015 at 15:06

2 Answers 2

5
$\begingroup$

Expanding my comment:

The natural map $H_*(X,A)\rightarrow H_*(X\cup_f Y, Y)$ is an isomorphism, this is the so-called "excision axiom".

The map $\pi_i(X,A)\rightarrow \pi_i(X\cup_f Y, Y)$ is an isomorphism through $i<n+m$, where $n,m$ are the connectivities of the maps $A\rightarrow X$, $A\rightarrow Y$, cf. Hatcher, theorem 4.23.

To see that it cannot generally hold, consider $X=D^n$, $A=\partial D^n$, $Y=pt$. The map takes the form $$ \pi_i(D^n,\partial D^n)\rightarrow \pi_i(S^n) $$ The left side is isomorphic to $\pi_{i-1}(\partial D^n)$, and the map coincides with the suspension homomorphism $\pi_{i-1}(S^{n-1})\rightarrow \pi_i(S^n)$. This is not an isomorphism.

This is not surprising at all, since excision is more or less the thing that axiomatically characterizes homology. In fact, the standard calculation of $H_*(S^n)$ uses basically only excision.

$\endgroup$
1
$\begingroup$

There is more to be said in the case of $\pi_*$. Of course we assume all the spaces are connected and pointed. Let $Z= X \cup_f Y$. Then we have a triad $(Z:Y,X)$ whose homotopy groups were first studied by Blakers and Massey, see this ncatlab reference.

There is also some more information which can be obtained using the techniques given in the EMS Tract vol 15 (2011) partially titled Nonabelian Algebraic Topology (NAT) (pdf available). Thus we can consider the homotopical excision morphism $$\varepsilon_n: \pi_n(X,A) \to \pi_n(Z,Y).$$ Note that there is a morphism $\lambda: \pi_1(A) \to \pi_1(Y)$ induced by $f: A \to Y$, and the displayed groups are modules over these fundamental groups if $n >2$, and crossed modules if $n=2$. Suppose the pair $(X,A)$ is $(n-1)$-connected. Then $(Z,Y)$ is $(n-1)$-connected and $$\pi_n(Z,Y) \cong \lambda_*(\pi_n(X,A)),$$ the "induced" module if $n>2$ and induced crossed module if $n=2$. This result is Corollary 5.4.2 of NAT if $n=2$ and Theorem 8.3.9 of NAT if $n>2$. Notice that if $n=2$ this is a nonabelian result: NAT contains a number of calculations using this result, which generalises a Theorem of J.H.C. Whitehead on free crossed modules in his paper "Combinatorial Homotopy II", a Theorem which is sometimes stated, but rarely proved, in texts on algebraic topology. These results generalise the Relative Hurewicz Theorem and are Corollaries of a Higher Homotopy Seifert-van Kampen Theorem (HHSvKT).

Indeed, as stated in the ncatlab reference, the algebraic form of the Blakers-Massey Theorem, not just the connectivity part, is also a consequence of a more general HHSvKT, see this exposition.

Some expository presentations are available on my preprint page.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.