5
$\begingroup$

I am reading C. D. Sogge's book "Lectures on Non-Linear Wave Equations". As an exercise, I attempted to fill out the details of the proof of Theorem 5.1 (Local Existence of Solutions for Semilinear Wave Equations), but I got stuck in the last part of the proof regarding the blow-up... Allow me to first state the theorem and then my question.

Consider the equation $$ \left\{\begin{array}{ll}\square\, u(t,x) = F(u(t,x)),\; t>0\\ u(0,x) = f(x),\; \partial_tu(0,x)=g(x) \end{array}\right.\qquad\qquad(a)$$

Theorem 5.1. Assume that $F\in C^k$, $F(0)=0$, and that $f\in C_0^{k+1}(\mathbb{R}^3)$, $g\in C_0^k(\mathbb{R}^3)$, with $k = 1,2,\ldots$. then there is a $T > 0$ so that $(a)$ has a unique solution $u\in C^k([0,T]\times\mathbb{R}^3)$. If the supremum, $T_\ast$, of such times $T$ is finite then $\sup_x \lvert u(t,x)\rvert\to \infty$ as $t \to T_\ast$.

Question. I am having difficulties understanding the blow up part of the theorem. What is the best way of proving this blow-up phenomenon (the second half of Theorem 5.1)?

To this end, let us make the following assumption (this is proved in the book):

Assumption. Given a $C^k$ solution $u$ of ($a$) in $[0,T)\times\mathbb{R}^3$. If $\sup_{\{(t,x)\colon 0\leq t<T\}}\lvert u(t,x)\rvert <\infty$ then $u$ extends to a $C^k$ function in the closed strip $[0,T]\times\mathbb{R}^3$.

Attempt. Under the assumption of local existence, according to the definition of $T_\ast$, there is a $u$ being a $C^k$ solution of ($a$) in $[0,T_\ast)\times\mathbb{R}^3$. To prove the second half of the theorem, let us show that if $$\lim_{t\to T_\ast}\sup_x\lvert u(t,x)\rvert \text{ exists in } \mathbb{R}$$ then $T_\ast = \infty$, that is, u in $C^k$ can be extended indefinitely. Now, it can be shown, according to our assumption above, that $u$ can be extended to a $C^k$ solution in the closed strip $[0,T_\ast]$. To prove the result, it remains to show that there exists $T > T_\ast$ such that $u$ extends to $[0,T_\ast]\cup [T_\ast,T)$.

My idea was then to use the first half of the theorem (local existence) on the following problem:

$$ \left\{\begin{array}{ll}\square\, \tilde{u}(t,x) = F(\tilde{u}(t,x)),\; t>T_\ast\\ \tilde{u}(T_\ast,x) = u(T_\ast,x),\; \partial_t\tilde{u}(T_\ast,x)=u(T_\ast,x) \end{array}\right.\qquad\qquad(b)$$ This is not a viable strategy, as can be seen easily: The local existence of a solution $u$ in $C^k$ solving $(a)$ requires that $f$ be $C^{k+1}$-smooth, but the local existence theorem guarentees no more than $u(T_\ast,x)$ being of class $C^k$, that is, the initial data in $(b)$ does not have the sufficient regularity needed.

This is migrated from:

https://math.stackexchange.com/questions/1198583/blow-up-for-semi-linear-wave-equation

$\endgroup$

1 Answer 1

2
$\begingroup$

The regularity mentionned in the theorem is not accurate, for two reasons. The first is that the spaces ${\cal C}^k$ don't behave well with PDEs. Often, it is better to work with ${\cal C}^{k,\alpha}$ with $\alpha\in(0,1)$.

The second and deeper reason is that the solutions have what is called a co-normal regularity. Physicists say that the solution is polarized. Let me explain this with the one-dimensional case ($x\in\mathbb R$). Then the equation reads $$(\partial_t+\partial_x)(\partial_t-\partial_x)u=F(u).$$ from this, you deduce that the quantity $w:=(\partial_t-\partial_x)u$ has a better regularity in the direction of $\partial_t+\partial_x$ than in other directions. In other words, $(\partial_t-\partial_x)w$ is more regular than $\partial_tw$ and $\partial_x w$ separately.

In three space dimensions, this can be quantified using pseudo-differential operators. But again, appropriate regularity results are directional, or polarized. The important theorems for propagation of regularity are due to Egorov and Taylor.

$\endgroup$
1
  • $\begingroup$ How may I improve on the theorem, to show that $C^{k,\alpha}$ regularity on the initial data suffices for the conclusion? $\endgroup$ Mar 21, 2015 at 15:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.