0
$\begingroup$

In using-lax-milgram-to-find-a-weak-solution-in-an-intersection-of-sobolev-spaces the weak solution for $$ -\Delta^2 u = f \in L^2(U)\\ \\ u|_{\partial U}=\Delta u|_{\partial U} = 0 $$ was discussed, I have a question about the week solution of $$ \Delta^2 u + u = f \in L^2(U)\\ \\ u|_{\partial U}=\Delta u|_{\partial U} = 0 $$ I think I should use coupled elliptic PDE theory, Any hint or suggestion is helpful for me.

In advanced thanks from anyone who tries to help me. I also asked this question in and got solution by dear @Tomas (thanks to him) link

$\endgroup$

1 Answer 1

2
$\begingroup$

Minus the bi-Laplacian, i.e. your operator $-\Delta^2$, is negative semidefinite (indeed, negative definite with your boundary conditions) on $L^2(U)$ as soon as you can define $-\Delta^2$ weakly by applying Gauss-Green formulae (this is certainly possible under mild assumptions on the boundary of your domain).

Therefore, 1 is certainly outside the spectrum of your operator, i.e., $$ 1-(-\Delta^2) $$ has a bounded inverse: This is all you need. You will certainly have a weak solution in $H^2(U)$. If your boundary is nice enough that you can define your operator not merely in a weak sense, but on the natural domain $H^4(U)$, then for any $f\in L^2(U)$ your solution will be even in $H^4(U)$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.