bio  website  math.haifa.ac.il/~seva 

location  Israel  
age  52  
visits  member for  4 years, 2 months 
seen  7 hours ago  
stats  profile views  3,045 
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17h

revised 
Cardinality of the prime divisor set of a kpower sum
added 8 characters in body 
17h

answered  Cardinality of the prime divisor set of a kpower sum 
Dec 14 
awarded  Nice Answer 
Dec 4 
revised 
The divisors of $p1$ and highdegree residues modulo $p$
tag added 
Dec 4 
comment 
The divisors of $p1$ and highdegree residues modulo $p$
Greg: No such reasons  but I'd be equally happy with a notsonice proof! 
Dec 4 
asked  The divisors of $p1$ and highdegree residues modulo $p$ 
Nov 30 
revised 
Sets of coprime numbers
edited body; edited tags 
Nov 27 
comment 
Biquadratic reciprocity for $p\equiv 1\pmod 4$ and $q\equiv 3\pmod 4$
@Lucia: I see, thanks! 
Nov 26 
comment 
Does this function have any exponential growth?
For $a$ and $x$ given, what is the maximum of $x^n\exp(a^n/x)/n!$ over all $n$? 
Nov 26 
comment 
Does this function have any exponential growth?
Have you optimized by $n$? What is the largest term of this series for $a$ and $x$ given? 
Nov 23 
comment 
Biquadratic reciprocity for $p\equiv 1\pmod 4$ and $q\equiv 3\pmod 4$
@Lucia: How about $q=3$, $p=13=3^2+2^2$, $\sigma=1$, in which case $b=2$ and $q\mid b+1$? Also, is it implicitly assumed that $p\equiv 1\pmod 8$ (this condition is mentioned a couple of lines above the equality in question)? 
Nov 23 
comment 
Biquadratic reciprocity for $p\equiv 1\pmod 4$ and $q\equiv 3\pmod 4$
@Lucia: I noticed this, but there seems to be a problem with this assertion as if, say, $p\equiv 1\pmod q$, then one can choose both $\sigma=1$ and $\sigma=1$, while I cannot see any reason for $\left(\frac{b+1}q\right)$ and $\left(\frac{(b1)}q\right)$ to be equal to each other. I do not have Lemmermeyer's book handy to check the assertion. 
Nov 23 
revised 
Biquadratic reciprocity for $p\equiv 1\pmod 4$ and $q\equiv 3\pmod 4$
added 89 characters in body 
Nov 23 
asked  Biquadratic reciprocity for $p\equiv 1\pmod 4$ and $q\equiv 3\pmod 4$ 
Nov 11 
answered  Existence of arithmetic function satisfying a certain property 
Nov 11 
revised 
Is ${\rm lcm}\{{\rm ord}_p(q)\colon q\mid p1,\ q>2\}>\sqrt p\ \,$?
added 70 characters in body; edited title 
Nov 10 
awarded  Nice Question 
Nov 10 
asked  Is ${\rm lcm}\{{\rm ord}_p(q)\colon q\mid p1,\ q>2\}>\sqrt p\ \,$? 
Nov 9 
awarded  Enlightened 
Nov 9 
awarded  Nice Answer 