bio  website  regularize.wordpress.com 

location  Braunschweig, Germany  
age  36  
visits  member for  4 years, 2 months 
seen  yesterday  
stats  profile views  1,781 
Professor at TU Braunschweig.
Area: Inverse problems, regularization theory, applied functional analysis, mathematical image processing.
1d

comment 
Image of (right) inverse trace map $\xi\colon H^{\frac 12}(\partial\Omega) \to H^1(\Omega)$ dense in $H^1(\Omega)$?
Ok, right  I thought that I had a basic misconception about the problem… 
1d

comment 
journal to submit mathematic books' review
The German "Mathematische Semesterberichte" publishes such reviews (probably only in German). 
1d

reviewed  Close How to construct a graph with arbitrarily large girth and large chromatic number? 
1d

reviewed  Leave Open Image of (right) inverse trace map $\xi\colon H^{\frac 12}(\partial\Omega) \to H^1(\Omega)$ dense in $H^1(\Omega)$? 
1d

comment 
Image of (right) inverse trace map $\xi\colon H^{\frac 12}(\partial\Omega) \to H^1(\Omega)$ dense in $H^1(\Omega)$?
Isn't solving the respective Dirichlet problem saying that the image contains $H^{3/2}$? 
Dec 16 
reviewed  Close Derangement,recursion and circular permutation 
Dec 16 
reviewed  Close Alexander duality theorem 
Dec 12 
reviewed  Leave Open $\Delta$ is generator, $u\in D_{loc}(\Delta) \cap L_{loc}^{\infty}$ and $\varphi \in D(\Delta) \cap L^{\infty}$, then $u\cdot \varphi \in D(\Delta)$? 
Dec 12 
reviewed  Leave Open The singular value of $F(\theta)=\sin\theta\int_{a}^{a}e^{ikz\cos\theta}f(z)dz.$ 
Dec 11 
revised 
What is an extragradient method?
corrected spelling 
Dec 10 
answered  Galerkin Projection on Integral Operators 
Dec 10 
answered  What is an extragradient method? 
Dec 7 
comment 
Banach space of discontinuous functions(Killing continuous functions)
"Appropriate quotient space" Do you have an idea how this space looks like (or how the space which you divide by)? I guess the quotient contains all characteristic functions of all points and then it wouldn't be separable in the first norm. The second norm looks pretty weired to me… 
Dec 4 
comment 
$Ax=b$ in a function space
I am not sure what you are after. Do you want to show that the solution depends continuously on the matrix? Are you especially interested in the case where $A$ gets singular? 
Nov 27 
awarded  Notable Question 
Nov 25 
accepted  Geometric measures different from Hausdorff 
Nov 25 
comment 
Continuous versions of tensors/ Tensors with infinite indices?
A situation where this works pretty straightforward is the case of functionals on $L^2$ (also on $L^p$ with $1<p<\infty$). There, the functionals are identified with functions, e.g. $(L^2)'=L^2$ and the tensor product of $L^2$ with itself is simple enough (en.wikipedia.org/wiki/Tensor_product_of_Hilbert_spaces). 
Nov 25 
comment 
Reference for a strong intermediate value theorem for measures
Actually, your statement is not strictly stronger than the result the OP is asking for since he wants the sets $S_t$ to be nested. 
Nov 20 
reviewed  Leave Open “Almost” zeta function 
Nov 19 
comment 
Removing constraints in convex optimization
Well, ehm, actually I don't see it either… Adapted my answer which is only a "partial answer" now… 