bio | website | |
---|---|---|
location | ||
age | ||
visits | member for | 4 years, 11 months |
seen | Dec 13 '10 at 21:30 | |
stats | profile views | 172 |
May
5 |
awarded | Good Answer |
Sep
18 |
awarded | Yearling |
Apr
17 |
awarded | Nice Answer |
Dec
10 |
answered | Abstract Thought vs Calculation |
Dec
10 |
comment |
Can we alter the axioms of Euclidean space to have $\mathbb{Q}^3$ as a unique model?
For me a more natural candidate would be the $A^3$, where $A$ is the set of real rational integers. Otherwise, you would end up with certain standard curves (which physisist are interested) only having finitely many points. The question is then: what is arclenght or area and how do you calculate it? |
Dec
9 |
comment |
Direct proof of irrationality?
Is using the fact that any non-integer algebraic integer is irrational considered a proof by contradiction? What about using that $x^2-2$ is irreducible (by Eisenstein) thus has only irrational real roots? |
Nov
23 |
comment |
Are Penrose tilings universal? Do aperiodic universal tilings exist?
A 1x1 square and a 2x1 ddomino tile is universal. Also any set containing a 1x1 tile and a set of "supertiles" build from 1x1 tiles is universal. You can do the same on any lattice: pick a fundamental cell and supertiles build by copies from the fundamental cell (for example, hexagons and triangles would work; or a pararlelogram and half of it). I suspect that this is actually the only possibe case, but not sure. I am pretty sure that no aperiodic tile can be universal. |
Nov
7 |
comment |
fibonacci series mod a number
Also note that the order of $GL_2(\Z_k)$ is much smaller than $n$, and the order of the matrix divides this order. If $l$ is the reminder of $n$ divided by this order, then $A^n=A^l \mod p$. Last but not least it is enough to consider the subgroup of matrices of $det =\pm1$. |
Nov
3 |
revised |
Invertible matrices satisfying $[x,y,y]=x$.
added 38 characters in body |
Nov
3 |
answered | Invertible matrices satisfying $[x,y,y]=x$. |
Oct
30 |
awarded | Commentator |
Oct
30 |
comment |
How should one think about non-Hausdorff topologies?
An elementary often used example of this type is the trig circle. When we look to the trig circle we view it as $\R/ 2\pi \Z$, yet often we work with real numbers not classes. |
Oct
28 |
comment |
Does $\frac{\mbox{lcm}(1,2,\dots,n+1)}{\mbox{lcm}(1,2,\dots,n)}\to\infty$?
There exists a "simple" formula for the seuence: $$ \frac{{\rm lcm} (1,2,3,.., n+1)}{\rm lcm} (1,2,3,.., n)}$$ is $p$ if (n+1)= p^ \alpha$ for some prime $p$ and $1$ otherwise. |
Oct
28 |
revised |
When are infinitely many points in the orbit of a polynomial integers?
deleted 27 characters in body |
Oct
28 |
revised |
When are infinitely many points in the orbit of a polynomial integers?
added 79 characters in body; added 12 characters in body; added 221 characters in body |
Oct
28 |
answered | When are infinitely many points in the orbit of a polynomial integers? |
Oct
27 |
comment |
describe subsets of the integers closed under the binary operation Ax+By
Actually if $A=2, B=-1$ or more generarily $A+B=1$ the minimal set $S$ is $S=\{ 1 \}$. |
Oct
27 |
revised |
describe subsets of the integers closed under the binary operation Ax+By
added 384 characters in body |
Oct
27 |
answered | describe subsets of the integers closed under the binary operation Ax+By |
Oct
24 |
comment |
Finding the determinant of a matrix with LU composition
Is there any reason why you want to calculate the determinant this way? This looks like an overkill, row reduction is much faster and as far as I know the easy LU decomposition algorithms include row-reducing the matrix. If you are really interested in the LU decomposition, there are couple algorithms listed on Wikipedia. A good description of the process (and for many other basic math results) is also given at this page: tutorial.math.lamar.edu/Classes/LinAlg/LUDecomposition.aspx |