bio | website | math.stanford.edu/~rmbellov |
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visits | member for | 5 years, 3 months |
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stats | profile views | 1,856 |
Oct 7 |
awarded | Yearling |
Jul 2 |
awarded | Curious |
Jun 21 |
revised |
Finiteness for separated residually finite modules
deleted 276 characters in body |
Jun 21 |
asked | Finiteness for separated residually finite modules |
Dec 23 |
comment |
Fiber functors to derived categories
Is it really true that $G$ linearly reductive implies $\delta=0$? For example, consider a cts homomorphism $\Gamma\rightarrow G(k)$ where $\Gamma$ is a procyclic group ($k$ could be discrete or have an interesting topology). Then the functor $V\mapsto V^\Gamma$ may not be exact, but the group cohomology $H^i(\Gamma,V)$ is likely computed by the complex $V\rightarrow V$, where the map is $\gamma-1$ for a topological generator $\gamma$ of $\Gamma$. If $V\mapsto V^\Gamma$ is exact, it looks to me like I get 2 $G$-torsors (one for $H^0$, one for $H^1$), but if not, I don't think $\delta=0$. |
Dec 22 |
awarded | Nice Question |
Oct 7 |
awarded | Yearling |
Jun 25 |
awarded | Citizen Patrol |
Jan 15 |
answered | the dual abelian scheme |
Oct 7 |
awarded | Yearling |
Oct 4 |
awarded | Nice Question |
Sep 30 |
accepted | Are D_dR and D_st “potentially comparable”? |
Sep 30 |
comment |
Are D_dR and D_st “potentially comparable”?
Great, thanks! |
Sep 29 |
asked | Are D_dR and D_st “potentially comparable”? |
Jul 3 |
awarded | Enlightened |
Jul 3 |
awarded | Nice Answer |
Jul 2 |
comment |
Some help in digesting a paragraph in the introduction of Deligne/Rapoport's “Les Schemas de Modules de Courbes Elliptique”
Yes, we're thinking of $(\mathbf{Z}/n\mathbf{Z})^2$ as a group scheme. Over any base scheme $S$, the scheme structure on $(\mathbf{Z}/n\mathbf{Z})_S^2$ is just $n^2$ disjoint copies of $S$. |
Jul 2 |
awarded | Enlightened |
Jul 2 |
awarded | Nice Answer |
Jul 2 |
answered | Some help in digesting a paragraph in the introduction of Deligne/Rapoport's “Les Schemas de Modules de Courbes Elliptique” |