Impact
~15k
people reached
- 0 posts edited
- 0 helpful flags
- 7 votes cast
Oct
7 |
awarded | Yearling |
Oct
7 |
awarded | Yearling |
Jul
2 |
awarded | Curious |
Jun
21 |
revised |
Finiteness for separated residually finite modules
deleted 276 characters in body |
Jun
21 |
asked | Finiteness for separated residually finite modules |
Dec
23 |
comment |
Fiber functors to derived categories
Is it really true that $G$ linearly reductive implies $\delta=0$? For example, consider a cts homomorphism $\Gamma\rightarrow G(k)$ where $\Gamma$ is a procyclic group ($k$ could be discrete or have an interesting topology). Then the functor $V\mapsto V^\Gamma$ may not be exact, but the group cohomology $H^i(\Gamma,V)$ is likely computed by the complex $V\rightarrow V$, where the map is $\gamma-1$ for a topological generator $\gamma$ of $\Gamma$. If $V\mapsto V^\Gamma$ is exact, it looks to me like I get 2 $G$-torsors (one for $H^0$, one for $H^1$), but if not, I don't think $\delta=0$. |
Dec
22 |
awarded | Nice Question |
Oct
7 |
awarded | Yearling |
Jun
25 |
awarded | Citizen Patrol |
Jan
15 |
answered | the dual abelian scheme |
Oct
7 |
awarded | Yearling |
Oct
4 |
awarded | Nice Question |
Sep
30 |
accepted | Are D_dR and D_st “potentially comparable”? |
Sep
30 |
comment |
Are D_dR and D_st “potentially comparable”?
Great, thanks! |
Sep
29 |
asked | Are D_dR and D_st “potentially comparable”? |
Jul
3 |
awarded | Enlightened |
Jul
3 |
awarded | Nice Answer |
Jul
2 |
comment |
Some help in digesting a paragraph in the introduction of Deligne/Rapoport's “Les Schemas de Modules de Courbes Elliptique”
Yes, we're thinking of $(\mathbf{Z}/n\mathbf{Z})^2$ as a group scheme. Over any base scheme $S$, the scheme structure on $(\mathbf{Z}/n\mathbf{Z})_S^2$ is just $n^2$ disjoint copies of $S$. |
Jul
2 |
awarded | Enlightened |
Jul
2 |
awarded | Nice Answer |