Laurent Moret-Bailly
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Registered User
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Jun 15 |
answered | Schemes over a noetherian local ring and its completion |
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May 21 |
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Degree of a finite locally free group scheme over a base scheme of characteristic p OK if "connected" means "with connected fibers". But I suspect the OP means "connected" literally. |
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May 12 |
awarded | ● Enlightened |
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May 12 |
awarded | ● Nice Answer |
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May 12 |
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First order decidability of rings vs Diophantine decidability @SJR: I agree, but my feeling is also (for the same reason) that examples should be easier to come by. |
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May 9 |
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First order decidability of rings vs Diophantine decidability @SJR: Thanks for this nice example. It is in a sense a bit disappointing since a key point here, as was noted in the comments, is the choice of $\mathbb{Z}$ as the subring of coefficients. In fact, if we choose $\mathbb{Q}(t)$ instead, then the existential theory of $\mathbb{R}(t)$ is not e.c: this goes back at least to Denef. What surprises me here is the first order undecidability without extra constants. |
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May 7 |
revised |
First order decidability of rings vs Diophantine decidability edited tags |
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May 6 |
awarded | ● Nice Question |
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May 6 |
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First order decidability of rings vs Diophantine decidability As SJR notes, I guess equations should have coefficients in some fixed (recursive) subring of $R$ in order for decidability to make sense. Likewise, first order formulas are in the language of rings augmented with constants from such a subring. |
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May 6 |
asked | First order decidability of rings vs Diophantine decidability |
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May 2 |
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morphism between two elliptic curves over a local field It is not trivial since there are always quadratic twists (besides, is not a group!). The point here is that any nontrivial twist of $X$ must have bad reduction. |
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May 1 |
accepted | Example of codim 1 regular embedding that is not an effective Cartier divisor? |
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May 1 |
answered | Example of codim 1 regular embedding that is not an effective Cartier divisor? |
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May 1 |
accepted | morphism between two elliptic curves over a local field |
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May 1 |
answered | morphism between two elliptic curves over a local field |
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Apr 24 |
accepted | Dimension of formal fiber |
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Apr 23 |
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The notion of multiplicity in algebraic geometry With the notation in the definition of $\overline{\mu}$, assume $P$ is a singular point. Then in general there is an $f\in\mathcal{O}_{X,P}$ such that $\mu_f(I)=1$, but none such that $\overline{\mu}_f(I)=1$. |
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Apr 23 |
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Bound for the degree of the field of definition for a closed point of a variety There is something wrong with your TeX. The math doesn't show properly: specifically, the math italic alphabetic characters don't show at all. |
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Apr 22 |
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Dimension of formal fiber Standard fact in commutative algebra: Let $A$ be a noetherian ring (I am not sure about the minimal assumptions), $J$ an ideal such that $A$ is $J$-adically complete and separated. Let $M$ be an $A$-module. If $M$ is $J$-adically complete and separated and $M/JM$ is finitely generated, then $M$ is finitely generated. Apply this to $A=\mathbb{C}[[f_1,\dots,f_d]]$, $J=(f_1,\dots,f_d)$ and $M=\mathbb{C}[[t]]$. Things are even simpler if, say, $f_1$ is a uniformizer in $\mathbb{C}[[t]]$: then it is easy to see directly that $\mathbb{C}[[f_1]]=\mathbb{C}[[t]]$. |
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Apr 21 |
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Kawamata-Viehweg Vanishing Theorem for Excellent Surfaces @Omprokash Das: it is not true in general that you can embed $k(x)$ into $\mathcal{O}_{X,x}$ or even into the function field of $X$. Example: assume $k$ is not algebraically closed, take $X=\mathbb{P}^n_k$ and take for $x$ a closed point with residue field $\neq k$. Variant: same $X$ ($n\geq2$, $k$ arbitrary), $x$= generic point of a non-unirational subvariety, e.g. a curve of positive genus. |
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Apr 20 |
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Kawamata-Viehweg Vanishing Theorem for Excellent Surfaces I don't understand "over $k(x)$". Clearly $S$ is a two-dimensional local scheme with closed point $\mathrm{Spec}\,k(x)$, but in general it is not a $k(x)$-scheme in any natural way. |
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Apr 19 |
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Equivalent definitions of ample bundles @Serge: the question is what is meant by "generate the stalk". With your phrasing, it should mean "generate the stalk $E_x$ as an $\mathcal{O}_{X,x}$-module". And then of course it is true for $E=\mathcal{O}_{X}$.
In condition 1 of the question, "$E_x$" should be understood as the stalk at $x$ tensored with the residue field. An even then, that version of the definition works only if you work with rational points over an algebraically closed field. |
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Apr 19 |
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Equivalent definitions of ample bundles @Serge: $\mathcal{O}_X$ is always globally generated! |
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Apr 16 |
answered | Dimension of formal fiber |
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Apr 6 |
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Finite extensions of residue fields of Henselian DVRs Maybe I misunderstand the question, but what if you start with an extension $L/F$ which is not simple and then take $K=F((t))$? |
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Apr 2 |
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Is the image of discrete set under an open map discrete? @Nik: Oops, sorry. |
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Apr 2 |
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Is the image of discrete set under an open map discrete? Here is a simpler one: if $t\in\mathbb{R}$ is irrational, the image of $t\mathbb{Z}$ under the projection $\mathbb{R}\to\mathbb{R}/\mathbb{Z}$ is not discrete. |
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Mar 7 |
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Is the universal closed subscheme reduced? The $G$-invariant part of a reduced scheme is not reduced in general: take $\mathbb{Z}/2\mathbb{Z}$ acting on the curve $xy=0$ by exchanging coordinates. |
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Mar 6 |
accepted | Open idempotents in modules over a local ring |
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Mar 6 |
revised |
Open idempotents in modules over a local ring added 360 characters in body |
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Mar 6 |
revised |
Open idempotents in modules over a local ring added 767 characters in body |
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Mar 6 |
answered | Open idempotents in modules over a local ring |
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Mar 6 |
revised |
Which schemes can be presented as limits of smooth varieties? deleted 12 characters in body |
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Mar 6 |
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Which schemes can be presented as limits of smooth varieties? I didn't say the morphisms were dominant. That would mean $B$ is the direct limit of its smooth subalgebras, a much stronger condition, it seems. And I know nothing about the non-affine case. |
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Mar 6 |
answered | Which schemes can be presented as limits of smooth varieties? |
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Mar 4 |
accepted | Artin approximation theorems over non-regular rings/non-Noetherian rings |
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Feb 28 |
answered | Artin approximation theorems over non-regular rings/non-Noetherian rings |
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Feb 19 |
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Zero-cohomology of birational varieties As you define it, $f_*$ depends on the choice of $U_1$. |
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Feb 18 |
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Formal power series over a henselian ring More generally: if $A$ is a local ring and $I$ an ideal such that $A$ is $I$-adically complete and separated, then $A$ is henselian if (and only if!) $A/I$ is henselian. This is easy by observing that each $A_n:=A/I^n$ is henselian (because $A_{n,\mathrm{red}}$ is) and then inductively lifting roots to $A$. See Raynaud, LNM 169, I, §2 where this result is given as an exercise. |
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Feb 16 |
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Are f.g. projective modules free over total quotient ring of a reduced non-noetherian commutative ring This ring is local, so projective=free. |
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Feb 11 |
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Open subset in the flat topology on Spec(R) The only Zariski neighborhood of the closed point in a local scheme $X$ is $X$. So, $U=\mathrm{Spec\,}(R_P)$ and your condition just means that $S$ is stable under generalization. |
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Feb 10 |
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Complementation in an extension field It is well known that if $\mathbb{Q}$ is complemented in $\mathbb{R}$ you get nonmeasurable sets in $\mathbb{R}$. I don't think you can get this without some form of AC. |
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Feb 8 |
comment |
on trivialisation of T-torsors And what is $x$? |
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Feb 6 |
accepted | Are noetherian schemes generically Jacobson? |
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Feb 6 |
revised |
Are noetherian schemes generically Jacobson? added 58 characters in body |
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Feb 5 |
answered | Are noetherian schemes generically Jacobson? |
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Feb 5 |
accepted | purity for finite flat group schemes |
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Feb 5 |
answered | purity for finite flat group schemes |
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Feb 4 |
revised |
Are rational varieties simply connected? added 669 characters in body |
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Feb 4 |
awarded | ● ag.algebraic-geometry |

