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Just when I thought I was out, they pull me back in


7h
reviewed Close Is there such a thing as cyclic Hasse diagram for posets?
7h
reviewed Close If $f(x) = Ax$, show that for all $t \in \mathbb{R}$, the extreme $x_n = x_n(t)$ of polygon converges to $e^{At} x_0$
7h
reviewed Approve suggested edit on A Scalar Curvature Computation in Brendle Marques Neves' Min-Oo Conjecture paper
8h
comment A noncommutative analogy of the tube lemma
I removed the "ask WBJ" tag, which if it is to remain used should be used meaningfully. (WBJ is a Banach space theorist, not an operator algebraist)
8h
revised A noncommutative analogy of the tube lemma
rolled back to a previous revision
10h
reviewed Reject suggested edit on A Special Pair of Formulas
12h
reviewed Reopen Fixed point problem with a monotone vector as a fixed point?
17h
reviewed Reject suggested edit on nontrivial theorems with trivial proofs
18h
reviewed Reject suggested edit on nontrivial theorems with trivial proofs
18h
reviewed Close Linear Programm with matrix
1d
comment Finding a particular solution to the non-homogenous system
@adam Speaking as someone who sets homework questions and who also tries to do mathematical research, that claim just isn't really true.
1d
reviewed Leave Closed how to make Contravariant and Covariant tensors applicable to problems of curvatures in halfspace problems?
1d
revised proof non diagonalizable matrix is not an inner product
removed inappropriate jordan-algebras tag
1d
comment Measure generated by Semigroup $\exp[-t|p|]$
Why the "haar-measure" tag?
2d
comment Show that $\int_0^\infty \sin\left(x^2\right)dx$ converges, but that $\int_0^\infty \sqrt{\sin^2\left(x^2\right)}dx$ does not.
This question doesn't seem on-topic for MathOverflow. Voting to close
2d
comment Norm bound of a complex resolvent
@neil What other structure are you willing to put on your matrix $A$ (beyond trivial things like "being diagonal with real entries") in order to get "a better bound"? Generically I would think that since $\Vert A \Vert_\infty$ can be significantly bigger than $\rho(A)$ even when $A$ is Hermitian, the same phenomenon would occur for $\Vert B \Vert_\infty$
2d
comment Norm bound of a complex resolvent
@FedericoPoloni I'm pretty sure from context it is the imaginary unit (multiplied by a copy of the identity matrix of the appropriate size)
2d
reviewed Leave Open Generators for the affine automorphism group of the octagon
2d
reviewed Leave Open Computing a Levenshtein edit distance between two strings when a particular set of string edits is forbidden
2d
reviewed Close Restarting a Markov chain