Gianni Bello
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Registered User
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May 30 |
awarded | ● Yearling |
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Feb 24 |
comment |
A classification of rational surfaces with effective $K$ Sorry, you are absolutely right about the first mistake, my proof is wrong. Anyway, just for the sake of truth, I didn't write that $-K_{X'}$ is ample; but it's not very important |
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Feb 24 |
revised |
A classification of rational surfaces with effective $K$ deleted 14 characters in body |
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Feb 24 |
answered | A classification of rational surfaces with effective $K$ |
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Jan 18 |
comment |
Irreducible divisors containing an arbitrary closed set Thanks quim (and Simone) for the proof. I choosed Olivier's as best answer, but your answer was very useful to understand that the answer is much closer to Bertini than I expected. I also believe that your (*) should be always true. Maybe, in the case $V_i$ is contained in the singular locus, you can blow-up $V_i$, take an exceptional divisor $E_i$ mapping surjectivly on $V_i$, and take something like an horizontal section of the morphism $E_i \to V_i$. |
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Jan 18 |
comment |
Irreducible divisors containing an arbitrary closed set Thanks Olivier! I really like this proof! |
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Jan 17 |
awarded | ● Citizen Patrol |
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Jan 17 |
asked | Irreducible divisors containing an arbitrary closed set |
