bio | website | |
---|---|---|
location | United States | |
age | ||
visits | member for | 3 years, 11 months |
seen | yesterday | |
stats | profile views | 3,200 |
Apr 4 |
accepted | Can non-isomorphic field extensions be isomorphic fields? |
Apr 4 |
asked | Can non-isomorphic field extensions be isomorphic fields? |
Mar 26 |
revised |
Do all $L^{\infty}(\mu)$ spaces have the Grothendieck property?
copy-editing |
Mar 26 |
comment |
Minimum Spanning Tree of Graph with Unknown Weights
Is the graph directed? $\:$ If no, then there are only $(n\cdot (n\hspace{-0.04 in}-\hspace{-0.05 in}1))/2$ edge weights. $\;\;\;\;$ |
Mar 9 |
accepted | $n$-in-a-row game on $\mathbb{R}^2$ |
Mar 3 |
comment |
Starting Hilbert's Program on the other end
@LucasK. : $\:$ If you can't drop them, then they're not unnecessary. $\;\;\;\;$ |
Mar 2 |
comment |
Is every graph the center of some other graph?
You don't actually need "long line"s of vertices, you can just attach another vertex to each of A and B. $\hspace{.6 in}$ |
Feb 28 |
accepted | Can Haar measure fail to be bi-invariant without conjugation shrinking a set? |
Feb 28 |
revised |
Can Haar measure fail to be bi-invariant without conjugation shrinking a set?
fixed grammar error caused by previous edit and reverted some spacing changes |
Feb 28 |
comment |
quantitative version of the rigidity of the 2-sphere
closed $\mapsto$ close $\:$ ? $\;\;\;\;$ |
Feb 28 |
asked | Can Haar measure fail to be bi-invariant without conjugation shrinking a set? |
Jan 31 |
awarded | Nice Question |
Jan 20 |
awarded | Popular Question |
Jan 16 |
comment |
Can a unit square be cut into rectangles that tile a rectangle with irrational sides?
Oh yeah. $\:$ (Although, presumably there should be a comma between $1/r$ and $a_1$.) $\hspace{1.4 in}$ |
Jan 16 |
comment |
Can a unit square be cut into rectangles that tile a rectangle with irrational sides?
In this particular case, one can replace "$f : \mathbb{R} \to \mathbb{R}$ be an additive group homomorphism" and "the Axiom of Choice" with "$f : \operatorname{span}_{\mathbb{Q}}(\{1,r,1/r\}) \to \mathbb{Q}$ be a linear map" and "linear algebra" respectively. $\:$ (That modification is what Clément described, although $\operatorname{span}_{\mathbb{Q}}$ is notation that I just made up.) $\:$ I do not know how to show a strong enough version of Schoenfield Absoluteness to deduce that result as a consequence, but I do know how to show that theorem's $\Sigma^1_1$ and $\Pi^1_1$ versions. $\;\;\;$ |
Jan 16 |
comment |
Can a unit square be cut into rectangles that tile a rectangle with irrational sides?
@DouglasZare : $\:$ Try applying that argument to "There does not exist a counter-example to AC." $\hspace{.59 in}$ |
Jan 10 |
comment |
Most 'obvious' open problems in complexity theory
@RyanO'Donnell : $\:$ This paper was published almost 2 years after you answered (by the other person who commented on this answer, which I almost didn't notice) and resolves your second example. $\;\;\;\;$ |
Jan 2 |
accepted | Can the Law of the Iterated Logarithm be strengthened? |
Jan 2 |
awarded | Nice Question |
Dec 5 |
awarded | Popular Question |