Johann Cigler
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Registered User
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20h |
answered | Sequences equidistributed modulo 1 |
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Apr 24 |
awarded | ● Yearling |
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Mar 4 |
comment |
Polynomials satisfying a three-term recurrence @ Peter: For the Chebyshev polynomials of the first kind $F$ is given as an integral on the interval [-1,1] with weight $\frac{1}{{\sqrt {1 - {x^2}} }}$, for the Chebyshev polynomials of the second kind with weight $\sqrt {1 - {x^2}} .$ |
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Mar 4 |
asked | Polynomials satisfying a three-term recurrence |
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Jan 30 |
asked | An identity for Hankel determinants |

