bio | website | maths.ox.ac.uk/~greenbj |
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location | Auckland, New Zealand | |
age | 37 | |
visits | member for | 4 years, 8 months |
seen | Dec 10 at 13:55 | |
stats | profile views | 12,168 |
I'm a professor at Oxford University, on sabbatical in New Zealand until April 2014
May 2 |
comment |
Historical question concerning Jordan's theorem
Igor, I believe this issue is comprehensively despatched in this paper of M. J. Collins: On Jordan's theorem for complex linear groups. J. Group Theory 10 (2007), no. 4, 411--423. He evaluates $j(n)$ for all $n$ and shows that $(n+1)!$ is the truth for $n \geq 71$ (and not for $n = 70$). But my interest is more in finding the simplest argument that gives some bound. |
May 2 |
awarded | Student |
May 2 |
asked | Historical question concerning Jordan's theorem |
May 2 |
awarded | Critic |
May 1 |
comment |
explicit big linearly independent sets
I think I agree! |
May 1 |
answered | explicit big linearly independent sets |
Apr 29 |
answered | Wanted: A constructive version of a theorem of Furstenberg and Weiss |
Apr 27 |
comment |
Are There Primes of Every Hamming Weight?
Qiaochu: no, but I believe it would give one in principle, in the sense that there is no ineffectivity arising from a potential Siegel Zero. People I know who have done the kind of explicit calculations necessary to extract actual bounds from arguments like this attest that it is very painful, and the bounds are often pretty awful to boot. |
Apr 27 |
awarded | Nice Answer |
Apr 27 |
awarded | Supporter |
Apr 27 |
awarded | Editor |
Apr 27 |
revised |
Are There Primes of Every Hamming Weight?
added 248 characters in body |
Apr 27 |
revised |
Are There Primes of Every Hamming Weight?
corrected a couple of typos; added 1 characters in body; added 14 characters in body |
Apr 27 |
answered | Are There Primes of Every Hamming Weight? |
Apr 26 |
awarded | Good Answer |
Apr 23 |
awarded | Nice Answer |
Apr 23 |
awarded | Teacher |
Apr 23 |
answered | What are some examples of colorful language in serious mathematics papers? |