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seen Aug 27 at 7:10

Sep
10
awarded  Enlightened
Aug
27
comment Algorithm for determining when polynomial iteration is bounded?
@Per: Thank you for the reference to the result on IFS undecidability. Alas, I don't see how to the IFS result here. However the second point, about the map $x\to x-1/x$ seems really interesting. Do you have a reference?
Aug
26
asked Algorithm for determining when polynomial iteration is bounded?
Jul
2
awarded  Curious
Jun
14
awarded  Enlightened
Jun
14
awarded  Nice Answer
Apr
28
awarded  Nice Answer
Apr
28
comment The existence of non-trivial homomorphisms $\prod_{n=1}^{\infty}\mathbb{Z}/\bigoplus_{n=1}^{\infty}\mathbb{Z}\to\mathbb{Z}/p\mathbb{Z}$
Nice. Alternatively, we can think of the last displayed item as a ring $R$, every element of which satisfies the equation $x^p=x$. So if $I$ is any maximal ideal of $R$, then the elements of the field $R/I$ all satisfy the same equation, whence $R/I$ is the $p$-element field.
Apr
27
answered The existence of non-trivial homomorphisms $\prod_{n=1}^{\infty}\mathbb{Z}/\bigoplus_{n=1}^{\infty}\mathbb{Z}\to\mathbb{Z}/p\mathbb{Z}$
Apr
6
awarded  Yearling
Mar
27
awarded  Popular Question
Feb
7
comment A question about how polynomials simplify under substitution
The sequence of revisions in this post is confusing, and may have misled you, for which I am sorry. Note that in the example you give, the group $M_0$ contains the nonconstant polynomial $x_1-x_0$.
Jan
20
awarded  Popular Question
Jan
11
revised Distribution of polynomials mod 1 using co-prime integers
added 9 characters in body
Jan
7
revised Floors of powers of reals, how much do the first few determine the next?
deleted 3 characters in body
Jan
6
revised Floors of powers of reals, how much do the first few determine the next?
edited body
Jan
6
revised Floors of powers of reals, how much do the first few determine the next?
edited body
Jan
6
answered Floors of powers of reals, how much do the first few determine the next?
Dec
24
comment Generating primes via composition of polynomials
Joe, Thank you for explaining the lay of the land.
Dec
24
comment Reducibility of polynomials maps
Yes. In fact $x^2+1$ does the job.