bio  website  voofie.com/user/ross_tang 

location  
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visits  member for  4 years, 10 months 
seen  Dec 5 '13 at 8:19  
stats  profile views  786 
Come here to write articles about mathematics, or discussion is welcome as well.
Dec 28 
awarded  Popular Question 
Dec 19 
awarded  Nice Question 
Sep 24 
awarded  Autobiographer 
Jul 2 
awarded  Curious 
Feb 28 
awarded  Popular Question 
Jun 19 
awarded  Popular Question 
Apr 9 
awarded  Yearling 
Feb 28 
awarded  Popular Question 
Sep 16 
answered  differentialdifference threeterm recursion 
Aug 18 
accepted  Why relativization can't solve NP !=P? 
Aug 15 
asked  Why relativization can't solve NP !=P? 
Aug 6 
comment 
Recursions which define polynomials
From another comment: "Can you give me some hints on how to generate (say, nontrivially) polynomials from your final formula, having a rational function a(t) ? Thanks! " He asked for method to generate polynomial from Max Alekseyev's formula. So I think providing a method is good enough. 
Aug 6 
comment 
Recursions which define polynomials
"I could not find any other example of a polynomial sequence generated in this way. I simply look for another such sequence of polynomials, so if you've ever seen something similar, please let me know. One more example would be a good answer to my question.", from author's comment. He just asked for 1 more example. And there is no mention of surprise? 
Aug 6 
revised 
Recursions which define polynomials
added 299 characters in body; added 80 characters in body 
Aug 6 
answered  Recursions which define polynomials 
Aug 2 
revised 
Solving partial difference equation
edited tags 
Aug 1 
comment 
Solving partial difference equation
Furthermore, for the Eulerian numbers, the order of difference equation for both the variables k and n are 1. But for the equation I asked, it is first order in n, but 2nd order in k. So I think they differ quite a lot. 
Jul 27 
comment 
Explicit formula for Euler zigzag numbers(Up/down numbers)
Wadim, you are right. It is really an explicit formula. I didn't notice it since I don't know Euler polynomials has explicit expansion. However, the formula you provided has an absolute sign. I think it will make all the manipulation and computation inconvenient? 
Jul 27 
comment 
Solving partial difference equation
You are right, Zudilin. Are you interested in finding a close form solution? Btw, the zigzags are just the tangent and secant number. Therefore that's not really mine. 
Jul 27 
comment 
Solving partial difference equation
Thank you for your answer. I read the page you mentioned in wikipedia. There is indeed closed form to Eulerian numbers: $A(n,m)=\sum_{k=0}^{m}(1)^k \binom{n+1}{k} (m+1k)^n.$ I don't know if I read it wrongly or not. Thanks!
