bio | website | dictionary.reference.com/… |
---|---|---|
location | Paris | |
age | 29 | |
visits | member for | 4 years, 9 months |
seen | 14 hours ago | |
stats | profile views | 889 |
In 2014, I obtained my PhD in math at CUNY Graduate Center. I enjoy mathematics.
In the song "Watching the Wheels," J. Lennon sings "There are no problems, only solutions." However, I prefer the simple Hegelian reversal of this statement: There are no solutions, only non-problems.
Oct 20 |
comment |
Probability of the maximum of a throw of an infinite number of $n$-sided dice being $k$
Actually, this way is very easy also $\sum_{j=0}^{k-1} j^m = \frac{1}{m}(B_m(k) - B_m)$ which will immediately imply the result which you proved. The Bernoulli numbers were a red-herring. |
Oct 20 |
accepted | Probability of the maximum of a throw of an infinite number of $n$-sided dice being $k$ |
Oct 20 |
comment |
Probability of the maximum of a throw of an infinite number of $n$-sided dice being $k$
ah, yes, now the other hint makes sense too. Thanks for your help. Your answer implies that $(B_m(k)-B_m)/mn^m$ goes to zero as $m$ approaches infinity provided $n>1$. I thought that maybe there is a way to prove this second fact directly. |
Oct 20 |
comment |
Probability of the maximum of a throw of an infinite number of $n$-sided dice being $k$
Thanks for your hint. Yes, it is true, but the events $E_i$ given by $\{(l_j) \mid l_i = n\}$ are not mutually exclusive. I should say that neither probability theory nor analysis are my specialty so perhaps I missed the hint. |
Oct 20 |
asked | Probability of the maximum of a throw of an infinite number of $n$-sided dice being $k$ |
Sep 30 |
awarded | Explainer |
Aug 14 |
answered | Vanishing of Motivic Cohomology |
Aug 14 |
revised |
Vanishing of Motivic Cohomology
fixed a couple of typos |
Aug 14 |
suggested | approved edit on Vanishing of Motivic Cohomology |
Jan 1 |
awarded | Yearling |
Dec 28 |
accepted | formally étale morphisms which are also universally closed |
Dec 23 |
answered | Integration on Compact Semirings |
Dec 21 |
comment |
formally étale morphisms which are also universally closed
yes, you are right on both counts. the premise of the question is more or less wrong with regards to formally étale morphisms. and, for étale morphisms, the best one can say is finite étale covers. but of course one can study finite pro-étale covers or finite formally étale covers. |
Dec 14 |
comment |
formally étale morphisms which are also universally closed
yes, it the second case f is finite etale. I guess not much can be said if I relax noetherian condition. |
Dec 13 |
asked | formally étale morphisms which are also universally closed |
Nov 23 |
awarded | Civic Duty |
Nov 19 |
comment |
algebraic multivariate power series over a field
Sure, my pleasure. I can think of another proof in the univariant case. I believe it should follow from cell-decomposition for definable subassignments in the language of Denef-Pas over $\mathbb{Q}[[X]]$, but this model-theoretic. Even though this is neither here nor there, I would like to know how to prove the multivariant case model-theoretically. |
Nov 19 |
awarded | Vox Populi |
Nov 19 |
awarded | Enthusiast |
Nov 17 |
revised |
algebraic multivariate power series over a field
added 14 characters in body |