7,093 reputation
12448
bio website www-fourier.ujf-grenoble.fr/…
location Grenoble, France
age 34
visits member for 4 years, 8 months
seen 13 hours ago
I am a teacher and researcher at Université Joseph Fourier.

2d
comment If 2-manifolds are homeomorphic and smooth, are they diffeomorphic?
In dimension 2 the answers follows immediately from the classification of surfaces (be they closed or not, the latter classification is more complicated though).
2d
comment Stability of minimal surfaces
You shoudl state more precisely what you mean by "stable" here. This term is ambiguous, especially in the present context.
Nov
20
reviewed Approve suggested edit on Does knot Floer homology detect knot genus in rational homology spheres?
Nov
20
answered Equal-area projections of the hyperbolic plane
Nov
17
revised Is displacement controled by stable norm?
deleted 1 character in body
Nov
17
comment Is displacement controled by stable norm?
There are several things called stable norm, but I precisely defined what I meant by this term here. $\gamma(0)$ is the image of the point $0\in\mathbb{R}^n$ under the action of $\gamma$ (I could have written $\gamma$ instead, but it is looks natural to me this way). When you have such questions, please ask them and wait an answer before editing.
Nov
17
awarded  Nice Answer
Nov
17
awarded  Nice Answer
Oct
25
answered What can be said of the structure of a metric space without isosceles triangles?
Oct
24
comment Special retraction from a metric space onto an arc
@PedroPerez: sorry for my hasty (and now deleted) comment.
Oct
23
comment What is the expression of first eigen function of Laplacian on Hyperbolic plane?
You should be more precise: given the eigenvalue you ask about, I guess you are considering the Laplacian acting on $L^2$ functions. Also, you could note that you are interested in eigenfunctions up to isometries, but that could be considered implicitly obvious.
Oct
19
comment Parity of $\lfloor 1/(x y) \rfloor$ not equally distributed
Well, given any law on $\mathbb{N}$, you will see this kind of things happen: it is impossible to find a probability measure on $\mathbb{N}$ which gives weight $1/k$ to each of the classes modulo $k$, simultaneously for all $k$ (the weight of any number should be zero to meet that request).
Oct
18
comment CAT spaces and Metric Measure Spaces
There sure are, few paper do geometry without some kind of analysis. But I don't see how one could point you to something relevant with only that info. Ask google scholar, and explain what does not satisfy you in the result, but you have to give us something if you expect help.
Oct
17
comment CAT spaces and Metric Measure Spaces
That's my point: in your comments to my answer you seem to be searching for your question. "A link" is not very precise, apart from re-explaining the definitions I do not see what kind of answer you could expect (clearly, neither imply the other if that is what you meant). Moreover it seems like you drift further apart from your original question with each new comment, an additional reason why I think you should first think more about what you really want to ask. Or maybe SE is just not the kind of place for your question.
Oct
17
comment CAT spaces and Metric Measure Spaces
Now that some time has passed, I feel your question is really too vague and will not attract a definite answer. I wonder if we should close it, or maybe you can precise it? Can you explain what you are after and why?
Oct
15
answered CAT spaces and Metric Measure Spaces
Oct
11
comment Surfaces ruled through a subset of points
It seems to me that if a sequence of lines in $S$ converges to a line $L$, then (assuming $S$ is topologically closed) $L$ must also be in $S$. Doesn't this answer all your questions?
Oct
8
awarded  Nice Answer
Oct
3
reviewed Approve suggested edit on Higher Cerf Theory
Oct
1
comment The relation between Gromov hausdorff convergence and inverse limit of compact metric spaces
Gromov-Hausdorff convergence makes sense in the "space" of compact metric spaces up to isometry. So "being in a Euclidean space" does not make much sense her.