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bio website math.berkeley.edu/~vivek
location Berkeley, CA
age 31
visits member for 4 years, 5 months
seen 9 hours ago

2d
comment Different definitions of linkless graphs
yes, those are clearly different definitions. however the distinction is irrelevant for the purposes of that second paper, since flat implies [KKM]-linkless implies [RST]-linkless implies, as shown in [RST], the existence of some flat embedding.
Aug
26
revised Twist in identification with singular cohomology
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Aug
25
revised Twist in identification with singular cohomology
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Aug
25
answered Twist in identification with singular cohomology
Aug
22
revised How do I find coefficients of a product expansion
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Aug
22
revised How do I find coefficients of a product expansion
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Aug
22
comment How do I find coefficients of a product expansion
I am vaguely aware that there's an answer to this question of the form ``take a logarithm and do symmetric function combinatorics'', but I wasn't able to reconstruct the details.
Aug
22
asked How do I find coefficients of a product expansion
Aug
18
comment A group allowing exactly 7 group topologies
How can there be an infinite group with exactly 2 topologies? Shouldn't there always be at least 3 -- trivial, discrete, and co-finite?
Aug
18
comment A group allowing exactly 7 group topologies
@Noah S: A topology on a finite group is the pullback of the discrete topology on the quotient by the closed and normal subgroup given by intersecting of all closed subsets containing the identity. So topologies are the same as normal subgroups; the non-inclusivity condition is asking that any two nontrivial normal subgroups intersect only in the identity, so $G$ is the product of any two. If there are at least 3 nontrivial such subgroups, they must all be the same simple group $H$ and $G = H \times H$, and has $2 + |Aut(H)|$ nontrivial normal subgroups.
Aug
17
revised FIltrations on a vector bundle on a curve
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Aug
17
answered FIltrations on a vector bundle on a curve
Aug
11
reviewed Reject suggested edit on nontrivial theorems with trivial proofs
Aug
9
revised Building a genus-$n$ torus from cubes
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Aug
9
awarded  Enlightened
Aug
9
awarded  Nice Answer
Aug
9
revised Building a genus-$n$ torus from cubes
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Aug
8
revised Building a genus-$n$ torus from cubes
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Aug
8
revised Building a genus-$n$ torus from cubes
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Aug
8
revised Building a genus-$n$ torus from cubes
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