bio | website | users.mai.liu.se/hanlu09 |
---|---|---|
location | Linköping, Sweden | |
age | 44 | |
visits | member for | 5 years |
seen | 21 hours ago | |
stats | profile views | 371 |
Nov 14 |
awarded | Nice Answer |
Feb 19 |
comment |
Why do primes dislike dividing the sum of all the preceding primes?
(Nitpicking: The guy's name was Mertens, not Merten.) |
Aug 22 |
awarded | Autobiographer |
Aug 22 |
awarded | Yearling |
Jun 25 |
awarded | Excavator |
Sep 18 |
comment |
Examples of seemingly elementary problems that are hard to solve?
@suvrit: To the two different parenthesizations mentioned in the preceding sentence. |
Sep 13 |
comment |
Geometric interpretation of matrix minors
"Lindström", to be precise. |
Aug 13 |
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What are the Poisson tensors for which hamiltonians are left invariant?
Your terminology seems a little nonstandard. $X_f$ is usually called the Hamiltonian vector field associated to $f$. When one speaks of "the Hamiltionian", this refers the the function $f$. |
Feb 23 |
comment |
Elementary mathematical books
...and when I clicked it, I ended up at the Chern essay. (Perhaps not so surprising in hindsight, since both links point to the same URI.) |
Feb 8 |
comment |
Reference for working with the implicit function theorem
Broken link. Hopefully this works better: fr.wikipedia.org/wiki/… |
Feb 4 |
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Does this formula have a rigorous meaning, or is it merely formal.
@Dick: I think the new name was introduced for marketing reasons, and is mainly used by the followers of David Hestenes. |
Feb 3 |
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Does this formula have a rigorous meaning, or is it merely formal.
...and by the way, I wish I could refer you to the book that a colleague of mine is writing, but unfortunately it is not finished yet: mai.liu.se/~anaxe/GMA.html |
Feb 3 |
comment |
Does this formula have a rigorous meaning, or is it merely formal.
@Dick: GA is really just another name for Clifford algebras, and there are determinants everywhere if you do coordinate calculations in a Clifford algebra. For example, the highest graded part of the Clifford product of two (homogeneous) multivectors is the exterior product of those multivectors, and exterior product is related to determinants in a way that you're probably familiar with. |
Jan 24 |
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Volumes of n-balls: what is so special about n=5?
@unknown: Bob Palais, "$\pi$ Is Wrong", Opinion column in Math Intelligencer, Vol. 23, No. 3, 2001. |
Jan 9 |
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Bertrand theorem - central forces
Here's another reference that can be read on Google books: Boccaletti & Pucacco, Theory of orbits. |
Jan 8 |
answered | Bertrand theorem - central forces |
Dec 8 |
comment |
Never appeared forthcoming papers
@Victor: Here are two examples by Flaschka: scholar.google.com/… (although this might be considered "cheating", since the Phys Rev B paper was probably labelled "II" instead of "I" by accident). |
Nov 27 |
answered | Nice Classes of Non-Closable Operators |
Nov 26 |
awarded | Civic Duty |
Nov 7 |
comment |
can the Newton's identities and Dodgson's condensations be proved by Gessel-Viennot's lemma?
"Submitted on 19 Oct 2010"; that's pretty good timing! ;) |