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visits | member for | 4 years, 1 month |
seen | Apr 15 at 19:10 | |
stats | profile views | 1,401 |
Mar 18 |
comment |
A souped-up version of a question asked previously about uncountable subsets of topological spaces
Thanks. That certainly proves that property P does not imply second countability and one can take any second countable topological space for X. |
Mar 17 |
comment |
A souped-up version of a question asked previously about uncountable subsets of topological spaces
I must apologize! My previous comment is topsy-turvy. X should be the space that has property P and Z should be the countable space that is not second countable. But I would still like to know what is meant by the "topological sum" of these two spaces. |
Mar 17 |
comment |
A souped-up version of a question asked previously about uncountable subsets of topological spaces
@ Santi Sparado: Thanks for your answer. Perhaps you could clarify one point. Let Z be the space having property P. Is Y the set union of X and Z and is the set union of any base of X with any base of Z, a base of Y? I am just trying to understand clearly what "topological sum" means |
Mar 16 |
asked | A souped-up version of a question asked previously about uncountable subsets of topological spaces |
Mar 6 |
awarded | Yearling |
Feb 9 |
comment |
A question about tiling Hilbert Space
@Alexander Shamov: Thanks alot. That is very nice and I am amazed because I thought the answer would be negative. |
Feb 9 |
accepted | A question about tiling Hilbert Space |
Feb 8 |
asked | A question about tiling Hilbert Space |
Jan 11 |
comment |
Is there a simple topological proof for a topological theorem about $S^2$?
@ Ian and Sasha: Very nice! That is exactly what I was looking for. Quantum theorists prefer the proofs based on finite sets of points since these points can represent directions of "spin" of a particle which are being measured in an experiment. But the coloring theorem is almost purely topological, except for the "metric" stipulation involving "pi/2". So I was sure it would have a proof of the kind you have provided. Unfortunately I was not able to come up with such a proof myself. Many thanks. |
Jan 11 |
accepted | Is there a simple topological proof for a topological theorem about $S^2$? |
Jan 10 |
asked | Is there a simple topological proof for a topological theorem about $S^2$? |
Jan 1 |
comment |
A question about the Ordinal Definable elements of Power Sets
@Joel: Many thanks for answering all my questions and providing background that goes far beyond my rudimentary knowledge of forcing. My feeling about ordinal definability stems from my preference for set theories in which many undefinable sets exist (particularly undefinable real numbers). Intuitively, the languages in which most set theories are formalized contain only countably many formulae that can be used to define these sets. So I would like the class OD to be as small as possible. It seems to me rather counter-intuitive for all sets to be definable-which is what occurs with V=OD. |
Dec 31 |
accepted | A question about the Ordinal Definable elements of Power Sets |
Dec 30 |
asked | A question about the Ordinal Definable elements of Power Sets |
Dec 13 |
comment |
Some questions about functions of Ordinal Numbers
Thanks alot for all this information. I asked these questions in order to obtain a clearer intuitive picture of the set of admissible ordinal numbers, which is often defined in rather complicated ways. |
Dec 13 |
comment |
Some questions about functions of Ordinal Numbers
Thanks alot for all this information. I asked these questions in order to get a clearer intuitive picture of |
Dec 13 |
accepted | Some questions about functions of Ordinal Numbers |
Dec 12 |
asked | Some questions about functions of Ordinal Numbers |
Dec 8 |
awarded | Popular Question |
Dec 7 |
awarded | Nice Question |