903 reputation
1525
bio website
location
age
visits member for 5 years, 1 month
seen yesterday

Apr
8
asked Closed geodesics in free smooth loop space?
Mar
18
revised Reference for higher order Campanato Lemmas, e.g. `Sufficiently fast L^2 decay on balls to affine functions implies C^{1,\alpha}'
Edited after Willie Wong's answer to expand title
Mar
18
comment Reference for higher order Campanato Lemmas, e.g. `Sufficiently fast L^2 decay on balls to affine functions implies C^{1,\alpha}'
Thanks Willie, this is exactly it.
Mar
18
accepted Reference for higher order Campanato Lemmas, e.g. `Sufficiently fast L^2 decay on balls to affine functions implies C^{1,\alpha}'
Mar
18
asked Reference for higher order Campanato Lemmas, e.g. `Sufficiently fast L^2 decay on balls to affine functions implies C^{1,\alpha}'
Feb
13
comment Must the Lebesgue measure of a $\rho$ - neighbourhood of an $(n-2)$ - dimensional set be at least $c\rho^2$?
Thanks for the comment fedja, I see your point. I don't know what made me think it was true now.
Feb
13
asked Must the Lebesgue measure of a $\rho$ - neighbourhood of an $(n-2)$ - dimensional set be at least $c\rho^2$?
Oct
7
awarded  Nice Question
Oct
6
comment Why do roots of polynomials tend to have absolute value close to 1?
I know very little about the math going on in the background but a colleague demystified this for me by saying that basically it is a special feature of the basis you have chosen, namely the monomials. If you choose a different basis or even just weight each monomial by a factor, the roots will tend to congregate on a different set. Basically although a) any polynomial can arise and b) you chose them randomly... They aren't as generic as as you think; they've in fact been chosen in a special way.
Aug
31
awarded  Yearling
Aug
31
awarded  Disciplined
Aug
3
awarded  Necromancer
Jul
2
awarded  Curious
Jan
24
awarded  Popular Question
Jul
15
awarded  Nice Answer
May
24
awarded  Good Question
Mar
30
comment What's a mathematician to do?
Probably my favourite answer on MO.
Mar
21
answered Applications of Rademacher's Theorem
Mar
11
comment What goes wrong for the Sobolev embeddings at $k=n/p$?
I'm not sure I quite appreciate exactly what is being asked. You lay out two cases and then say that what is essentially just a third case is an example of the other two not working. You say that the Sobolev embedding theorem "fails" or "goes wrong" when $k=n/p$, but one might say that it is simply neither of the two cases you lay out at the start. Nothing "fails", it just happens to be its own special case.
Feb
27
awarded  Yearling