bio | website | maths.leeds.ac.uk/~mdaws |
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location | Leeds, UK | |
age | ||
visits | member for | 5 years, 2 months |
seen | Dec 7 at 20:20 | |
stats | profile views | 3,035 |
Oct 15 |
awarded | Yearling |
Sep 30 |
awarded | Explainer |
Aug 13 |
awarded | Nice Question |
Jul 7 |
accepted | “Minimal” group C*-algebra? |
Jul 3 |
revised |
Arveson's extension for normal completely positive maps
Showing that the final part is not correct. |
Jul 2 |
answered | Arveson's extension for normal completely positive maps |
Jul 2 |
awarded | Inquisitive |
Jul 2 |
awarded | Curious |
Jun 24 |
awarded | Nice Question |
Jun 24 |
asked | “Minimal” group C*-algebra? |
Jun 12 |
answered | Continuity of the product map |
Apr 15 |
revised |
What is “tilting” in the context of large deviations?
Removed backticks which were messing with the formatting |
Mar 29 |
awarded | Popular Question |
Mar 6 |
comment |
Can we expect $\left\||f|^{2}f-|g|^{2}g\right\|\leq C ||f-g||$ in the Banach algebra $A(\mathbb T)$ ?
Although, I must say that the whole $M=2\|f_0\|$ thing is very mysterious... |
Mar 6 |
comment |
Can we expect $\left\||f|^{2}f-|g|^{2}g\right\|\leq C ||f-g||$ in the Banach algebra $A(\mathbb T)$ ?
But that's not what the question asked: $f_0$ is fixed, this gives $M$ and then the OP specifically asks only for $f,g\in B_M$. If it was meant to be uniform, then why both with the $B_M$ condition? |
Mar 6 |
answered | Can we expect $\left\||f|^{2}f-|g|^{2}g\right\|\leq C ||f-g||$ in the Banach algebra $A(\mathbb T)$ ? |
Mar 5 |
comment |
Does anybody know if the Fourier algebra of SL(3,Z) has an approximate identity?
What do you mean by "somewhat technical partial converse"? Just Thm 1.11, namely some sort of tensoring against a group with a sufficient rich set of representations? |
Feb 13 |
awarded | Notable Question |
Nov 20 |
comment |
How a unitary corepresentation of a Hopf C*-algebra, deals with the antipode?
Okay, I'm not sure I have much deeper to say than that actually... |
Nov 20 |
comment |
How a unitary corepresentation of a Hopf C*-algebra, deals with the antipode?
Sure! But why the antipode behaves in this way is perhaps interesting (and, in some sense, forms the basis for the definition of the antipode in more complicated analytic quantum group settings). |