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bio website matthewdaws.github.io/…
location Leeds, UK
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visits member for 5 years, 10 months
seen Jul 19 at 21:02

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comment Ultraweak topology on B(X): Is the map X\otimes X* -> B(X)* isometric?
@YemonChoi: I would look at $B(X,X^{**})$ instead of $B(X^*)$, then we're asking if the ball of $B(X,X)$ is weak$^*$-dense in the ball of $B(X,X^{**})$. The PLR shows that this is true for finite-rank operators; and the metric approximation property allows you to reduce from all operators to just the finite-rank ones. If $X$ is reflexive, then there is nothing to prove. What I don't see is how to combine these two rather different viewpoints...!
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accepted “Minimal” group C*-algebra?
Jul
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revised Arveson's extension for normal completely positive maps
Showing that the final part is not correct.
Jul
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answered Arveson's extension for normal completely positive maps
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asked “Minimal” group C*-algebra?
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answered Continuity of the product map
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revised What is “tilting” in the context of large deviations?
Removed backticks which were messing with the formatting
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awarded  Popular Question
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comment Can we expect $\left\||f|^{2}f-|g|^{2}g\right\|\leq C ||f-g||$ in the Banach algebra $A(\mathbb T)$ ?
Although, I must say that the whole $M=2\|f_0\|$ thing is very mysterious...
Mar
6
comment Can we expect $\left\||f|^{2}f-|g|^{2}g\right\|\leq C ||f-g||$ in the Banach algebra $A(\mathbb T)$ ?
But that's not what the question asked: $f_0$ is fixed, this gives $M$ and then the OP specifically asks only for $f,g\in B_M$. If it was meant to be uniform, then why both with the $B_M$ condition?