bio | website | |
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location | ||
age | ||
visits | member for | 1 year, 11 months |
seen | 9 hours ago | |
stats | profile views | 196 |
Jun
3 |
comment |
A circulant coin weighing problem
I just looked up weighing matrices but I don't see the connection to this problem yet. Could you expand on that please? |
Mar
8 |
comment |
Expected value of the minimum with limited independence
Can you show that there is a constant upper bound for $\mathbb{E}(X)$? |
Dec
14 |
revised |
Expected maximum inner product
deleted 71 characters in body |
Nov
27 |
awarded | Disciplined |
Sep
16 |
awarded | Yearling |
Sep
4 |
awarded | Nice Question |
Aug
27 |
awarded | Curious |
Aug
26 |
comment |
A conjecture about the entropy of matrix vector products
Thank you. Posted to mathoverflow.net/questions/179459/… . Please edit if it doesn't reflect your view accurately. |
Aug
26 |
comment |
A conjecture about the entropy of matrix vector products
Do you think it would be acceptable to pose your formulation as a new question? I have no ideas for how to approach it. |
Aug
3 |
comment |
A conjecture about the entropy of matrix vector products
Your "new part" looks like the core of the problem but I have to admit, looks no easier to me. It will be great if you (or anyone) has any ideas about this new formulation. |
Jul
26 |
awarded | Promoter |
Jul
26 |
revised |
A conjecture about the entropy of matrix vector products
added 16 characters in body |
Jul
24 |
revised |
A conjecture about the entropy of matrix vector products
edited title |
Jul
24 |
revised |
Puzzle on deleting k bits from binary vectors of length 3k
deleted 88 characters in body |
Jul
24 |
asked | A conjecture about the entropy of matrix vector products |
Apr
15 |
comment |
What is $\lim_{n\to\infty} \displaystyle \sum_{k=0}^{\lfloor n/2 \rfloor} \binom{n}{2k}\left(4^{-k}\binom{2k}{k}\right)^{\frac{2n}{\log_2{n}}}\,?$
Can I ask my question again in that case? Is the OP right that convergence depends on the constant in the exponent? |
Apr
13 |
comment |
What is $\lim_{n\to\infty} \displaystyle \sum_{k=0}^{\lfloor n/2 \rfloor} \binom{n}{2k}\left(4^{-k}\binom{2k}{k}\right)^{\frac{2n}{\log_2{n}}}\,?$
Is the OP right that convergence depends on the constant in the exponent? I can't immediately tell from your answer. |
Apr
4 |
awarded | Investor |
Feb
15 |
accepted | Smallest non-zero eigenvalue of a (0,1) matrix |
Feb
15 |
comment |
Smallest non-zero eigenvalue of a (0,1) matrix
There is nothing better than an explicit construction. Thank you. Although it would be great if I could accept the upper and lower bounds answers together. |