Impact
~64k
people reached
- 0 posts edited
- 0 helpful flags
- 69 votes cast
Jan
18 |
asked | Polynomials representing locally constant functions |
Jan
5 |
reviewed | Approve How to cite authors from any country correctly? |
Jan
4 |
comment |
Uncertainty principle for Mellin transform
To wit: if $f(x)$ decays like $exp(-x^r)$ as $x\to \infty$, then $M(\sigma+i\tau)$ cannot decay as fast as $exp(-c |\tau|)$ for any $c>\pi/2r$. (Well, unless $f$ is $0$ almost everywhere, obviously.) |
Jan
4 |
answered | Uncertainty principle for Mellin transform |
Dec
12 |
reviewed | Approve Convex hulls of families of probability measures |
Dec
12 |
awarded | Nice Question |
Dec
11 |
asked | Non-congruence normal subgroups of $SL_2(\mathbb{Z}[1/2])$ |
Nov
5 |
revised |
Quotients of an extension of the Higman group
added 249 characters in body |
Nov
4 |
revised |
Quotients of an extension of the Higman group
added 134 characters in body |
Nov
3 |
revised |
Quotients of an extension of the Higman group
added 174 characters in body |
Nov
3 |
revised |
Quotients of an extension of the Higman group
added 169 characters in body |
Nov
1 |
revised |
Normal subgroups of an extension of the Higman group
added 206 characters in body |
Oct
31 |
asked | Quotients of an extension of the Higman group |
Oct
30 |
comment |
Normal subgroups of an extension of the Higman group
Another example to work on (given that I seem to have ungraciously broken yours): what about $atatat^2$? I suspect its closure does contain $H$. Is the same true for every word of the form $a^{k_1} t a^{k_2} t a^{k_3} t^2$? |
Oct
30 |
comment |
Normal subgroups of an extension of the Higman group
In the last step, don't you get $H/N = \langle a,b|b a b^{-1} = a^2, a b a^{-1} = b^2\rangle$? And isn't that trivial? |
Oct
29 |
revised |
Normal subgroups of an extension of the Higman group
added 134 characters in body |
Oct
26 |
revised |
Normal subgroups of an extension of the Higman group
added 373 characters in body |
Oct
26 |
comment |
Normal subgroups of an extension of the Higman group
Ah, no, I see you do it tacitly at the very beginning. This makes me curious. If we remove the condition $t^4=e$ (but keep the other relations), must the group still be trivial? |
Oct
26 |
comment |
Normal subgroups of an extension of the Higman group
Thanks! I guess you did not use the condition $t^4=e$ at all to obtain $a=e$? |
Oct
24 |
comment |
Normal subgroups of an extension of the Higman group
No, I don't think so; conjugate $t^2$ by $a$, say. |