bio  website  ucs.louisiana.edu/~avm1260 

location  Lafayette, LA, USA  
age  45  
visits  member for  4 years, 8 months 
seen  3 hours ago  
stats  profile views  2,974 
With the move of MathOverflow into the SE network, this account is now associated with dormant accounts in math.SE and other sites in the network. While I plan to continue my (generally lowlevel) participation in MO, my current plans do not include restarting my participation in those other sites. Therefore, I will be ignoring any comments or pings that reach me from those sites, unless and until I resume my active participation there.
I remain "gone for the foreseeable future" from math.SE, tex.SE, and meta.SE.
Please do not send me private email to call my attention to comments, questions, or other matters related to those sites. Thank you.
2d

reviewed  Approve suggested edit on Second HardyLittlewood Conjecture theme 
Oct 5 
reviewed  Approve suggested edit on The Convergence of Jacobi and GaussSeidel Iteration 
Sep 30 
awarded  Explainer 
Sep 8 
reviewed  Approve suggested edit on Amenability as a geometric property 
Sep 7 
reviewed  Approve suggested edit on Dimension of totally reflexive modules 
Sep 3 
reviewed  Approve suggested edit on Irreducibility of $x^mg(y)$ 
Sep 1 
revised 
Group structure on an arbitrary completely regular topological space that makes $(x,y)\mapsto xy^{1}$ continuous at $(1,1)$
more accurate title 
Aug 23 
comment 
Who defined and who coined “module”?
I would say, in answer to your edit, that if that is your definition of "define" then Dedekind both coined and defined the term (just like he coined the term "ideal", as opposed to "ideal number"). Noether generalized, just like she generalized a lot of the theory of rings and ideals, but according to Stillwell in the work quoted by anon, she was fond of saying "Es steht schon bei Dedekind" ("It is already in Dedekind") when talking about ideals/modules. 
Aug 11 
comment 
Selfduality of the subgroup lattice of $G\times H$
I realize the observation above doesn't answer the question; but it now looks more like: if the product of two lattices is selfdual, is one of the lattices selfdual? And that does indeed look suspect. 
Aug 10 
comment 
Selfduality of the subgroup lattice of $G\times H$
The condition on the orders of $G$ and $H$ imply that every subgroup of $G\times H$ is of the form $A\times B$ with $A\leq G$ and $B\leq H$. Hence, the lattice of subgroups of $G\times H$ is equal to the product of the lattices of the subgroups of $G$ and of $H$. 
Aug 8 
revised 
Combination of two recent problems about finite groups of square orders
fix formatting 
Aug 4 
reviewed  Reject suggested edit on Existence of solutions of a polynomial system 
Aug 3 
comment 
Classification of 2groups with center of index 4
@StefanKohl: Just to nitpick, it's very easy to characterize all groups with center of index 2: they do not exist.... 
Aug 3 
comment 
On direct product of capable groups
In general, you cannot hope for these kind of converses without conditions; just the fact that the product of two cyclic groups of the same order is always capable, but a nontrivial cyclic group is not, should tell you that this will not in general work; making one of the factors nilpotent does not, in my mind, give you enough leverage. The problems lie much deeper. 
Aug 3 
comment 
Existence a finite capable pgroup of class two
I do have to ask: why would we care? i.e., where did these conditions come from, and why should we impose them on a group? 
Aug 2 
revised 
Existence a finite capable pgroup of class two
deleted 1 character in body 
Aug 2 
revised 
Existence a finite capable pgroup of class two
title was ungrammatical; attempt at a grammatical one. 
Aug 2 
answered  Existence a finite capable pgroup of class two 
Jul 3 
reviewed  Reject suggested edit on nontrivial theorems with trivial proofs 
Jul 2 
awarded  Curious 