bio | website | ucs.louisiana.edu/~avm1260 |
---|---|---|
location | Lafayette, LA, USA | |
age | 45 | |
visits | member for | 5 years, 4 months |
seen | 8 hours ago | |
stats | profile views | 3,309 |
With the move of MathOverflow into the SE network, this account is now associated with dormant accounts in math.SE and other sites in the network. While I plan to continue my (generally low-level) participation in MO, my current plans do not include restarting my participation in those other sites. Therefore, I will be ignoring any comments or pings that reach me from those sites, unless and until I resume my active participation there.
I remain "gone for the foreseeable future" from math.SE, tex.SE, and meta.SE.
Please do not send me private e-mail to call my attention to comments, questions, or other matters related to those sites. Thank you. Also, as I no longer participate in those sites, I do not wish to be sent, by private e-mail, questions that you can just as well ask on those sites. I would have thought it was obvious, but apparently I need to say so explicitly.
Jun 20 |
revised |
Representation of finite group
add tags |
Jun 12 |
reviewed | Reject Is regularity closed under products? |
Jun 7 |
revised |
Min number of primes up to n
fix some latex |
Jun 4 |
comment |
For a ring $k$ and a set $X$, what are the $k$-algebra homomorphisms $k^X \to k$?
@TomLeinster: Yes, you should keep LaTeX to a minimum in titles, and you definitely don't want to have an all-LaTeX title. On the other hand, ASCII art and pseudo-latex ( k^x )seem like a bad idea when you are talking about such a small part of the title. This is not a LaTeX-heavy title... |
Jun 4 |
revised |
For a ring $k$ and a set $X$, what are the $k$-algebra homomorphisms $k^X \to k$?
latex title |
Jun 1 |
reviewed | Edit Quintic Equation |
Jun 1 |
revised |
Quintic Equation
format edited |
Jun 1 |
comment |
Quotients of finitely generated nilpotent groups
@YCor: I think yo umean "torsionfree" where you say "finite", but yes, I see there would be issues because the factors for $H/N_3$ (e.g., $(H/N_3)^{\rm ab}$) could be strictly proper factors of the corresponding ones for $H$, so we are not sure that $H$ itself has torsionfree factors. Thanks. |
Jun 1 |
comment |
Quotients of finitely generated nilpotent groups
@YCor: Wouldn't we be able to do the same thing in general by induction on the class? First, go to a torsionfree subgroup of finite index $N$, so we may assume $N$ Is torsionfree. Then find a subgroup $H$ of finite index that contains $N_{k+1}$ such that $H/N_{k+1}$ has the desired property. But since $N_{k+1}\subseteq Z(N)\cap H\subseteq Z(H)$, then the commutator subgroup of $H/N_{k+1}$ is "essentially" the same as that of $H$ because the center is marginal in the commutator bracket, so the fact that $H/N_{k+1}$ has torsionfree quotients shoudl give $H$ does as well... |
May 31 |
comment |
Quotients of finitely generated nilpotent groups
@YCor: Thanks! I confess to not knowing it before. |
May 31 |
reviewed | Edit Can one estimate the distribution of eigenvalues of a matrix by its Cauchy/Stieltje transform? |
May 31 |
revised |
Can one estimate the distribution of eigenvalues of a matrix by its Cauchy/Stieltje transform?
Corrections |
May 30 |
comment |
Quotients of finitely generated nilpotent groups
@YCor: How do we get to $N$ torsionfree to begin with? |
May 30 |
revised |
Boundedness of solutions of a difference equation
As long as there was a recent bump, let's get rid of all those nasty typos, the annoying "how to proof", etc. |
May 29 |
comment |
Quotients of finitely generated nilpotent groups
For arbitrary class, I would try to do some induction; assuming we can do it for class $c$, with $N$ of class $c+1$, we could try finding a subgroup of finite index $H$ such that $H/N_{c+1}$ has the desired property in $N/N_{c+1}$, so that the only possible problem lies in $H_{c+1}$, and then take a finite index subgroup of $H$ given by adequate powers of the generators so that we are in the torsionfree part of $H_{c+1}$ once we get down to it. |
May 29 |
reviewed | Reject A question on an set of 8 matrices related to the SU(3) generators |
May 29 |
revised |
Quotients of finitely generated nilpotent groups
delete stray paragraph from draft version |
May 29 |
answered | Quotients of finitely generated nilpotent groups |
May 29 |
comment |
Quotients of finitely generated nilpotent groups
@DaveWitteMorris: I'm not sure I follow what you are writing... are you reversing the roles of $N$ (original group) and $H$ (group we are looking for)? If we take the original group to be the integral Heisenberg group, then since $N/N_2\cong \mathbb{Z}^2$, $N_2/N_3\cong \mathbb{Z}$, and $N_3=\{e\}$, we can just take $H=N^1=N$. How did I get $H^2$ and $H^4$? |
May 29 |
comment |
Quotients of finitely generated nilpotent groups
Is there some reason that you cannot just take $N^k$, where $k$ is a common multiple of the exponents of the torsion subgroups of all $N_i/N_{i+1}$ ? |