MathOverflow will be down for maintenance for approximately 3 hours, starting Monday evening (06/24/2013) at approximately 9:00 PM Eastern time (UTC-4).

Dustin Clausen

4,090
Reputation
6033 views
Is this your account?

Registered User 

Name Dustin Clausen
Member for 3 years
Seen 10 mins ago
Website
Location MIT
Age
Jun
10
awarded  Nice Answer
May
29
awarded  Nice Answer
May
28
accepted Explicit description of boundary map in algebraic K-theory
May
28
revised Explicit description of boundary map in algebraic K-theory
added 87 characters in body
May
27
awarded  Necromancer
May
27
awarded  Self-Learner
May
27
answered Explicit description of boundary map in algebraic K-theory
Apr
10
awarded  Enlightened
Apr
10
awarded  Nice Answer
Apr
10
accepted Etale homology via étale cosheaves
Apr
4
awarded  Good Answer
Feb
14
comment Etale homology via étale cosheaves
(for a nice reference from the Cech perspective, see Mitchell's paper math.uiuc.edu/K-theory/0346/topk.pdf in section 3.)
Feb
14
comment Plus construction considerations.
Well, in general it's not deterministic, even if you know Steenrod actions on the homology. I had in mind whatever you can get in low degrees from considerations as in Goodwillie's answer. In our case that gives K_1 = H_1(GL(R)) and K_2 = H_2([GL(R),GL(R)]) and K_3 = H_3(universal central extension of [GL(R),GL(R)]), but there we stop because H_3 doesn't have as nice a group theory interpretation. Another fact (at least provided the H-space is actually a loop space) is that the rational homotopy maps isomorphically to the primitives of the Hopf algebra structure on the rational homology.
Feb
14
comment Etale homology via étale cosheaves
No, I literally mean Pontryagin dual. Think of it this way: etale cohomology with Z/l^infty coefficients should be equal to continuous homomorphisms from \pi_1(X) to Z/l^infty, or to continuous homomorphisms from H_1(X;Z_l) to Z/l^infty. This just means that H^1(X;Z/l^infty) is Pontryagin dual to H_1(X;Z_l).
Feb
14
answered Etale homology via étale cosheaves
Feb
10
awarded  Enlightened
Feb
10
awarded  Nice Answer
Feb
10
awarded  Yearling
Feb
9
accepted Plus construction considerations.
Feb
9
answered Plus construction considerations.
Jan
26
comment Conceptual proofs for the computation of the structure sheaf
Just a comment: your first proof is an unwinding of the simple proof "apply faithfully flat descent to the map A --> \prod_{u\in U} A_u".