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Aug
24
comment Finding integer points on elliptic curves via divisibility conditions like $(a+b)^2 \mid (2b^3+6ab^2-1)$
Note that the heuristic I gave also suggests that apart from finitely many exceptions, the largest square factor of $m^3-2$ is at most $(m\log m)^2$, say. So this is certainly in a very delicate range!
Aug
24
answered Finding integer points on elliptic curves via divisibility conditions like $(a+b)^2 \mid (2b^3+6ab^2-1)$
Aug
24
reviewed Leave Closed Maximal score for the 2048 game
Aug
24
reviewed Leave Open Repetend digit graphs for $1/n$ in base $b$
Aug
24
reviewed Leave Open Finding integer points on elliptic curves via divisibility conditions like $(a+b)^2 \mid (2b^3+6ab^2-1)$
Aug
23
comment Smooth sums of coprime smooth integers
@StefanKohl: This is not specified, but could be calculated with some effort. It would likely be quite large.
Aug
23
revised Smooth sums of coprime smooth integers
Reference to recent work added
Aug
23
comment Separation of lattice points on the Mordell elliptic curve
To clarify: your question is not about the difference between $x^3$ and $y^2$ (Hall's conjecture), but rather about the difference between those values of $x$ for which the spacing between $x^3$ and its nearest square is small (below $\sqrt{x}$). Is that correct?
Aug
23
reviewed Leave Closed Aperiodic set of corner Wang Tile
Aug
23
reviewed Close Why calculus textbooks do not include the natural integration constants in the tables of integrals?
Aug
22
reviewed Close book for probability
Aug
22
reviewed Leave Open A group allowing exactly 7 group topologies
Aug
21
reviewed No Action Needed Controling mixed derivatives
Aug
21
reviewed Close Where to find (personal) motivation
Aug
20
revised The Diophantine equation $x^p - 4y^p = z^2$
Added top level tag
Aug
20
comment The Diophantine equation $x^p - 4y^p = z^2$
@FelipeVoloch: Good point!
Aug
20
revised The Diophantine equation $x^p - 4y^p = z^2$
added 354 characters in body
Aug
20
comment The Diophantine equation $x^p - 4y^p = z^2$
@GHfromMO: Thanks for pointing that out! I'll also add a link to Darmon's paper.
Aug
20
answered The Diophantine equation $x^p - 4y^p = z^2$
Aug
20
comment The Diophantine equation $x^p - 4y^p = z^2$
Well if there were infinitely many solutions, it would contradict a Theorem of Darmon and Granville! See math.mcgill.ca/darmon/pub/Articles/Research/12.Granville/… .