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visits | member for | 1 year, 4 months |
seen | 13 hours ago | |
stats | profile views | 6,315 |
Nov 16 |
reviewed | Leave Open number of divisors |
Nov 15 |
comment |
$\pm1$-polynomials with a maximal non-real root
Very interesting! Clearly there's something to think through there. |
Nov 14 |
reviewed | Close Pronunciation: Dijkstra |
Nov 14 |
reviewed | Leave Open Infected square |
Nov 14 |
reviewed | Reviewed Converting p-adic to decimal |
Nov 14 |
reviewed | Leave Open Grothendieck -sad news |
Nov 13 |
reviewed | Close Oldest photographed mathematician |
Nov 13 |
comment |
Bound for sums of bounded multiplicative functions that are zero at primes
The number of square-full integers up to $x$ is $O(x^{\frac 12})$. |
Nov 12 |
comment |
$\pm1$-polynomials with a maximal non-real root
Interesting! I don't know what it means! You could also look at the Odlyzko-Poonen situation, and see if there is a pattern to the polynomials there that have largest non-real root. Maybe that problem will have a similar feature to what you're seeing here? |
Nov 12 |
reviewed | Close Integer-valuedness of a polynomial determined by output of first n integers? |
Nov 11 |
reviewed | Reject nontrivial theorems with trivial proofs |
Nov 11 |
reviewed | Reject Refereeing a Paper |
Nov 11 |
reviewed | Leave Closed iterative solution better than analytic solution? |
Nov 10 |
reviewed | Reviewed Looking for the name of an infinite sequence |
Nov 10 |
comment |
A number theoretic identity
Do those who voted to close see an easy proof of this? It seems a remarkable fact to me (if true), but maybe I'm missing something obvious. The objection that the problem is unmotivated doesn't seem correct to me: if the numbers from $1$ to $m$ are permuted randomly without fixed points, the expected value of $|a-\sigma(a)|$ would be the answer given. It's not at all clear to me why multiplication by $\lambda$ should always give exactly this answer. |
Nov 10 |
answered | $\pm1$-polynomials with a maximal non-real root |
Nov 10 |
reviewed | Reopen A number theoretic identity |
Nov 9 |
comment |
$\pm1$-polynomials with a maximal non-real root
Most of the zeros of a $\pm 1$ polynomial will cluster around the unit circle, and get equidistributed in angle. So every point on the unit circle is a limit point of zeros. |
Nov 9 |
reviewed | Close Your experience of Computer Science/Programming in Mathematics Education? |
Nov 9 |
reviewed | No Action Needed Determining Roots of a Polynomial with Interval Estimates of Coefficients |