Lucia
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 Feb 5 comment Asymptotics of product of Euler's totient function (A001088)? Yes and it equals $\frac{1}{e}\prod_p (1-1/p)^{1/p}$. Feb 4 reviewed Leave Open Does the sum $\sum_{n=1}^{\infty}\frac{1}{p_n(p_{n+1}-p_n)}$ converge? Feb 2 comment natural radical and an algebraic expression in $\pi$ and/or $e$ I didn't really have anything to add to that one line. By all means include it in the question. (Ok here's one more line to go with my comment: the same constant also appeared in an old asymptotic formula of Bateman to count the number of integers $n$ for which $\phi(n)\le x$. This is why I recognized the Euler product at once, but it is just a coincidence.) Jan 30 comment natural radical and an algebraic expression in $\pi$ and/or $e$ $\zeta(2)\zeta(3)/\zeta(6)$. Jan 28 revised Upper bound on answer for Pell equation added 678 characters in body Jan 28 awarded Nice Answer Jan 28 revised Upper bound on answer for Pell equation added 1124 characters in body Jan 27 comment Upper bound on answer for Pell equation You only get from this a bound of $\exp(p^{1/2+\epsilon})$. Please see argument in my answer below. Jan 27 answered Upper bound on answer for Pell equation Jan 27 reviewed Reviewed Binomial Expansion for non-commutative setting Jan 27 reviewed No Action Needed Pointwise convergence of Fourier series, Fefferman's article Jan 25 reviewed Leave Open Polynomial factoring over finite fields Jan 25 awarded Enlightened Jan 24 reviewed Close Definition: Grigelionis Process?ch Jan 20 reviewed Close How do i show that:$\prod\frac{p^2+1}{p^2-1}=\frac{5}{2}$ without using properties of Riemann zeta function? Jan 15 comment Characters of permutation groups @GjergjiZaimi: You're probably right. I just didn't know what to call it! But Polya + cycle index covers the bases. Jan 15 answered Characters of permutation groups Jan 13 reviewed Leave Open Greatly expanded new edition of a Bourbaki chapter on algebra? Jan 7 answered Improvement of a bound on divisor distributions from “Divisors” (Hall and Tenenbaum)? Jan 6 awarded Nice Answer