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Feb
5
comment Asymptotics of product of Euler's totient function (A001088)?
Yes and it equals $\frac{1}{e}\prod_p (1-1/p)^{1/p} $.
Feb
4
reviewed Leave Open Does the sum $\sum_{n=1}^{\infty}\frac{1}{p_n(p_{n+1}-p_n)}$ converge?
Feb
2
comment natural radical and an algebraic expression in $\pi$ and/or $e$
I didn't really have anything to add to that one line. By all means include it in the question. (Ok here's one more line to go with my comment: the same constant also appeared in an old asymptotic formula of Bateman to count the number of integers $n$ for which $\phi(n)\le x$. This is why I recognized the Euler product at once, but it is just a coincidence.)
Jan
30
comment natural radical and an algebraic expression in $\pi$ and/or $e$
$\zeta(2)\zeta(3)/\zeta(6)$.
Jan
28
revised Upper bound on answer for Pell equation
added 678 characters in body
Jan
28
awarded  Nice Answer
Jan
28
revised Upper bound on answer for Pell equation
added 1124 characters in body
Jan
27
comment Upper bound on answer for Pell equation
You only get from this a bound of $\exp(p^{1/2+\epsilon})$. Please see argument in my answer below.
Jan
27
answered Upper bound on answer for Pell equation
Jan
27
reviewed Reviewed Binomial Expansion for non-commutative setting
Jan
27
reviewed No Action Needed Pointwise convergence of Fourier series, Fefferman's article
Jan
25
reviewed Leave Open Polynomial factoring over finite fields
Jan
25
awarded  Enlightened
Jan
24
reviewed Close Definition: Grigelionis Process?ch
Jan
20
reviewed Close How do i show that:$\prod\frac{p^2+1}{p^2-1}=\frac{5}{2}$ without using properties of Riemann zeta function?
Jan
15
comment Characters of permutation groups
@GjergjiZaimi: You're probably right. I just didn't know what to call it! But Polya + cycle index covers the bases.
Jan
15
answered Characters of permutation groups
Jan
13
reviewed Leave Open Greatly expanded new edition of a Bourbaki chapter on algebra?
Jan
7
answered Improvement of a bound on divisor distributions from “Divisors” (Hall and Tenenbaum)?
Jan
6
awarded  Nice Answer