bio | website | math.sunysb.edu/~vpingli |
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location | ||
age | ||
visits | member for | 4 years, 8 months |
seen | Sep 28 at 23:02 | |
stats | profile views | 900 |
Graduate student at SUNY stony brook (5th year PhD student).
Sep 24 |
awarded | Autobiographer |
Jul 2 |
awarded | Inquisitive |
Jul 2 |
awarded | Curious |
Nov 19 |
comment |
A continuous version of Teichmuller uniqueness
Sorry. I was being silly. |
Nov 19 |
accepted | A continuous version of Teichmuller uniqueness |
Nov 19 |
revised |
A continuous version of Teichmuller uniqueness
Changed an assumption |
Nov 19 |
comment |
A continuous version of Teichmuller uniqueness
Yes x is the norm of the Teichmuller map. Sorry, I am a novice in this field. So you are saying that if the $L^{\infty}$ norms of some Beltramis get close to the extremal $L^{\infty}$, then the corresponding q.c maps get close in the uniform topology (also I don't want just a subsequence but the entire sequence to converge)? If so, can you cite a reference. Thanks a million! |
Nov 19 |
asked | A continuous version of Teichmuller uniqueness |
Nov 14 |
answered | Solutions of the $\overline{\partial}$ equation in the upper half-plane |
Jun 18 |
awarded | Popular Question |
May 17 |
asked | Vector bundles on Stein Manifolds |
Apr 22 |
accepted | Density of smooth functions in Sobolev spaces on manifolds |
Apr 4 |
comment |
Density of smooth functions in Sobolev spaces on manifolds
For bounded domains in Euclidean space, this is true (Evans' book). It gets tricky when one wants to approximate by smooth functions that smooth upto the boundary. |
Apr 3 |
revised |
Density of smooth functions in Sobolev spaces on manifolds
Changed tags |
Apr 3 |
asked | Density of smooth functions in Sobolev spaces on manifolds |
Jan 29 |
awarded | Yearling |
Oct 26 |
comment |
monge-ampere operator
This isn't a complete answer, but may help. For smooth u_k, u_k >v is an open set. For non-smooth u, this is not necessarily the case. It may have a boundary. Just outside the boundary max(u,v) = v and inside max(u,v) = u. So, whilst testing the current against test functions whose support "ends" at the boundary, it isn't obvious (to me) that dd^c(max(u,v)) = dd^c (u). |
Sep 17 |
awarded | Popular Question |
Sep 4 |
accepted | Alexandrov-Bakelmann-Pucci maximum principle |
Sep 4 |
revised |
Alexandrov-Bakelmann-Pucci maximum principle
corrected typos |