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May
16 |
accepted | Orbits of the maximal compact subgroup on the light cone for $p$-adic groups |
May
7 |
awarded | Good Answer |
Apr
28 |
comment |
Orbits of the maximal compact subgroup on the light cone for $p$-adic groups
Thanks for the reposting and the clarification regarding SO(Q). |
Apr
27 |
comment |
Orbits of the maximal compact subgroup on the light cone for $p$-adic groups
Dear few_reps: I have read your answer and am trying to see if I can make your proof and the one given below by Paul work for SO(Q). Please repost your answer. I will give feedback soon. |
Apr
27 |
awarded | Popular Question |
Apr
20 |
comment |
Orbits of the maximal compact subgroup on the light cone for $p$-adic groups
Thank Paul, I fixed it. |
Apr
20 |
revised |
Orbits of the maximal compact subgroup on the light cone for $p$-adic groups
deleted 2 characters in body |
Apr
20 |
asked | Orbits of the maximal compact subgroup on the light cone for $p$-adic groups |
Apr
2 |
asked | A variant of Nelson-Hadwiger Problem on the chromatic number of the plane |
Mar
31 |
accepted | In what sense is the classification of all finite groups “impossible”? |
Jan
29 |
awarded | Yearling |
Oct
17 |
awarded | Popular Question |
Oct
16 |
awarded | Nice Answer |
Sep
11 |
awarded | Nice Question |
Sep
8 |
comment |
In what sense is the classification of all finite groups “impossible”?
@StefanKohl: Well, I take CFSG as a complete classification, even though it does not answer all questions that one can pose about the finite simple groups. Such a listing would be perfectly OK. My question is, whether there are any obvious obstruction that one cannot expect to come up with such a list for all groups. For instance, the classification of the groups of order $p^n$ gets increasingly complicated with $n$, but so does the classification of $n \times n$ matrices up to conjugacy (Jordan form), so in what sense is the classification of groups of prime power "impossible"? |
Sep
8 |
asked | In what sense is the classification of all finite groups “impossible”? |
Aug
24 |
awarded | Nice Answer |
Aug
23 |
comment |
A question about “Zariski dense” arguments
Yes, but there is no "subtraction" possible in the space $Y$ above. Let me rephrase the argument: the set of matrices $A$ with $p_A(A)=0$ is closed, (because it is the pre-image of $0$ under the map $ A \mapsto p_A(A)$ that $\{ 0 \}$). Since it contains a dense set, it has to be the entire space. You do not need to use the diagonal. |
Aug
23 |
answered | A question about “Zariski dense” arguments |
Aug
6 |
comment |
$p$-adic analogues of $SO(3)$
user52824: Thank you for the enlightening comment. I soon have to deal with several other cases (including different ${\mathbf Q}_p$-forms of ${\mathrm{SO}}_4$.) It would be great if you could please provide a reference that explains how to systematically find all these forms. |