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Jan
22
revised Discrete measures and discrete kernels
added 49 characters in body
Jan
22
comment Discrete measures and discrete kernels
I added the definition of support.
Jan
22
revised Discrete measures and discrete kernels
Added definition of $\text{supp}\mu.$
Jan
22
comment Discrete measures and discrete kernels
Well, $K(x,\cdot)$ is also defined for $x\neq x_k.$ So the question is, if $K$ is still measurable in $x$
Jan
21
asked Discrete measures and discrete kernels
Nov
19
accepted Relative interior and dense subsets
Nov
19
comment Relative interior and dense subsets
@Kallus: you want to give this as an answer?
Nov
18
comment Relative interior and dense subsets
But your second argument seems to be plausible...
Nov
18
comment Relative interior and dense subsets
I think you are mixing up interior with relative interior. The relative interior of a non-empty convex set is always nonempty!!!
Nov
18
revised Relative interior and dense subsets
edited body
Nov
18
asked Relative interior and dense subsets
Jun
6
awarded  Enthusiast
May
20
comment Existence of dominating measure for weak*-compact set of measures
What do you mean by universal property?Can you specify a bit more what you mean by compatibility in the first part?
May
17
accepted Existence of dominating measure for weak*-compact set of measures
May
16
awarded  Commentator
May
16
comment Existence of dominating measure for weak*-compact set of measures
This is really beautiful!The only thing I have still to think about is the existence of such a sequence $(\mathbb P_n){n\in\mathbb N}$...
May
16
comment Existence of dominating measure for weak*-compact set of measures
@Davide : Does a weka*-compact substet necessarily have to be totally ordered?
May
15
comment Existence of dominating measure for weak*-compact set of measures
@George Lowther : do you have a proof for this? So the answer given by Davide Giraudo is not true when the maps $Z$ are bounded?
May
14
comment Existence of dominating measure for weak*-compact set of measures
@Gerald Edgar: "...the usual way to define it is to use continuous $Z$." Maybe you realized that we are working on measurable spaces and there is no notion of continuity...
May
14
comment Existence of dominating measure for weak*-compact set of measures
I forgot boundedness! sorry