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Jan
12
comment System of polynomial equations: P(x)=P(y) rather than P(x)=0
Yes, I am looking for real solutions, and the fiber over the generic point has exactly $k$ points, so this answers perfectly the question. Thanks.
Jan
12
awarded  Scholar
Jan
12
accepted System of polynomial equations: P(x)=P(y) rather than P(x)=0
Jan
12
awarded  Student
Jan
11
asked System of polynomial equations: P(x)=P(y) rather than P(x)=0