Mart
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Unregistered User
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Jan 12 |
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The number of elements of order k in PGL(2, q) @Wei Zhou: By the sizes of conjugacy classes of PGL the size of the conjugacy class of an order-k cyclic subgroup $C$ must be $q(q-1)$ or $q(q+1)$. |
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Jan 12 |
awarded | ● Commentator |
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Jan 11 |
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The number of elements of order k in PGL(2, q) Now I know what is the size of the conjugacy class of an order-k cyclic subgroup C, but still I don't know what is the number of conjugacy classes of such subgroups C. By Tom's answer it must be $\phi (k)/2$. But why? Can anybody help me? |
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Jan 11 |
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The number of elements of order k in PGL(2, q) @Tom: I don't know you how get the number of elements of order k. |
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Jan 11 |
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The number of elements of order k in PGL(2, q) @Michael Zieve: Thank you. If possible give me more details of your answer. |
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Jan 11 |
asked | The number of elements of order k in PGL(2, q) |
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Dec 31 |
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A question on almost simple groups @Geoff Robinson: Thank you very much, it was most helpful! |
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Dec 30 |
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A question on almost simple groups @Geoff Robinson: Thanks. By Derek's answer if $S\unlhd G$ with $S$ simple and $G\leq Aut(S)$, then $p$ is prime divisor of $S$. Whether by your answer it implies that $p$ is prime divisor of $S$? |
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Dec 30 |
awarded | ● Student |
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Dec 30 |
asked | A question on almost simple groups |
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Dec 4 |
awarded | ● Scholar |
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Dec 4 |
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Prime divisor of finite group @Arturo Magindin: Thank you so much for your answer. |
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Dec 3 |
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Prime divisor of finite group @Arturo Magidin: Thanks. Note that $G$ is not $p$-group. |
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Dec 3 |
asked | Prime divisor of finite group |
