bio | website | maths.swan.ac.uk/staff/ejb |
---|---|---|
location | Swansea, Wales | |
age | ||
visits | member for | 2 years, 9 months |
seen | 15 hours ago | |
stats | profile views | 181 |
Jul
23 |
revised |
A problem in functional calculus
added 788 characters in body |
Jul
23 |
revised |
A problem in functional calculus
added 788 characters in body |
Jul
23 |
comment |
A problem in functional calculus
Thanks! That solves the problem. Now maybe I shall make a comment on the approximate identity stuff... |
Jul
23 |
accepted | A problem in functional calculus |
Jul
22 |
asked | A problem in functional calculus |
Jun
27 |
comment |
allowing `discontinuous functions' into a C* algebra
Very interesting... I shall have to look further into this, thanks for pointing it out. |
Jun
27 |
accepted | allowing `discontinuous functions' into a C* algebra |
May
8 |
answered | Example of a covariant derivative on a non-projective bundle |
May
8 |
revised |
Example of a covariant derivative on a non-projective bundle
for clarity |
May
8 |
comment |
Example of a covariant derivative on a non-projective bundle
Thanks - there is no chance for a locally trivial bundle to do this. But is there any sheaf-like structure (expressed as a module with connection over the algebra of functions) for which it can be done? |
May
8 |
asked | Example of a covariant derivative on a non-projective bundle |
May
8 |
awarded | Benefactor |
May
6 |
accepted | Identifying a Hopf algebra cohomology theory |
May
2 |
comment |
Identifying a Hopf algebra cohomology theory
OK, I have added more explanation - apologies for that. There is a way to reformulate the complex with no explicit invariants and no algebra structure. |
May
2 |
revised |
Identifying a Hopf algebra cohomology theory
better explanation of problem |
May
2 |
comment |
Identifying a Hopf algebra cohomology theory
The required action for the van Est spectral sequence is the full tensor product coaction (this is needed to get a non-trivial dependence on the coaction). I see now that my question was ambiguous on this point. If I remember correctly, the sequence without taking the invariants is acyclic - will check. |
May
1 |
comment |
Identifying a Hopf algebra cohomology theory
The product appears implicitly in the coaction on the tensor product. I am checking the reference - thanks! |
May
1 |
awarded | Promoter |
Apr
18 |
awarded | Yearling |
Apr
18 |
revised |
Identifying a Hopf algebra cohomology theory
spelling! |