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seen Jun 24 '13 at 20:36

Jun
25
awarded  Tumbleweed
Jun
24
comment Symmetric convex curve
@ Anton, I came back to the original question, since there is not a counterexample yet.
Jun
24
revised Symmetric convex curve
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Jun
22
comment Symmetric convex curve
@Anton, Did you forget to put $\epsilon \alpha+o(\alpha)$. Remember that I am asking of bi-Lipschitz mappings between curves (not between open domains).
Jun
20
comment Symmetric convex curve
@Anton: I didn't understand this argument indeed. How do you relate angles with bi-Lipschitz. Maybe it is not quasiconformal at the corrners.
Jun
20
comment Symmetric convex curve
@Anton. I guess that arc-length parametrization g is the best mapping for part. You can prove that $Lip(g)\le \pi/2 diam(γ)/2$, but this is not that I expect.
Jun
19
comment Symmetric convex curve
$Lip(f)=1/4 \sqrt{2} \pi$
Jun
19
comment Symmetric convex curve
The square in not a counterexample. Namely, assume as we may that the square $|\gamma|=2\pi$. Then by using arc-length parametrization $f: S^1\to \gamma$ we obtain that $Lip(f)=\sqrt{2}{4}\pi$.
Jun
19
comment Symmetric convex curve
@Sergei I meant that the map should be a homeomorphism, otherwise the question is trivial. Your projection maybe is not onto?
Jun
19
revised Symmetric convex curve
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Jun
19
comment Symmetric convex curve
@Anton, I have made some revision of the previous question.
Jun
19
revised Symmetric convex curve
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Jun
19
revised Symmetric convex curve
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Jun
18
revised Symmetric convex curve
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Jun
18
asked Symmetric convex curve
Jun
7
accepted Riemann isometry vs Euclidean bi-Lipschitz mapping
Jun
7
asked Riemann isometry vs Euclidean bi-Lipschitz mapping
May
21
comment Lipschitz map of the circle onto a triangle
Then you obtain $L^9$ growth of bi-Lipschitz constant.
May
20
asked Lipschitz map of the circle onto a triangle
May
19
comment Lipschitz map of the ellipse
The metric from the Euclidean plane is assumed and Mixon has the answer.