Peter Sheldrick
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 Nov 21 awarded Disciplined Oct 13 awarded Nice Answer Dec 7 awarded Scholar Dec 7 accepted Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ Dec 7 revised Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ added 113 characters in body; edited tags; deleted 6 characters in body Dec 7 comment Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ Hi, thanks for your work! This doesn't effect the proof, but if $q_n(x)=B_n(x)$ then $q_n(0)=B_n(0)=B_n$. It is $p(0)=1/(n+2)!$ so $p_n(0)q_n(0)+r_n(0)$=$B_n/(n+2)!-B_n/(n!(n+2)!)\neq 0$. So is $q_n(x)=B_n(x)/n!$? Dec 7 revised Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ edited body Dec 7 awarded Supporter Dec 7 awarded Student Dec 7 revised Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ edited tags; edited body Dec 7 comment Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ This question is (cross-posted)[math.stackexchange.com/questions/252928/… with math.stackexchange. Dec 7 asked Bernoulli number formula involving roots of Taylor polynomial of $\exp-1$ Nov 6 awarded Teacher Jun 21 awarded Organizer Jun 20 awarded Editor