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Peter Sheldrick
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
added 113 characters in body; edited tags; deleted 6 characters in body
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
Hi, thanks for your work! This doesn't effect the proof, but if $q_n(x)=B_n(x)$ then $q_n(0)=B_n(0)=B_n$. It is $p(0)=1/(n+2)!$ so $p_n(0)q_n(0)+r_n(0)$=$B_n/(n+2)!B_n/(n!(n+2)!)\neq 0$. So is $q_n(x)=B_n(x)/n!$?
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
edited tags; edited body
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
This question is (crossposted)[
math.stackexchange.com/questions/252928/…
with math.stackexchange.
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Bernoulli number formula involving roots of Taylor polynomial of $\exp1$
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