bio | website | halgebra.math.msu.su/staff/… |
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location | Moscow | |
age | ||
visits | member for | 2 years, 4 months |
seen | yesterday | |
stats | profile views | 1,179 |
Oct 1 |
awarded | Caucus |
Aug 31 |
comment |
A generalization of an old group problem
@nadal, (2) is not true (without additional assumptions); see Yves's comment. |
Aug 31 |
comment |
Basis removal gives a basis
Oh, thank you, @domotorp! |
Aug 31 |
comment |
Basis removal gives a basis
I do not understand about 28. Can you clarify? |
Aug 31 |
comment |
Basis removal gives a basis
@Will and domotorp: you are right of course; I edited this part. That was an incorrect generalisation of the 3-dimensional case. |
Aug 31 |
revised |
Basis removal gives a basis
deleted 36 characters in body |
Aug 30 |
comment |
Basis removal gives a basis
@fedja, if there is a pair of twins, then the other vectors must lie in some hyperplane $U$, because otherwise we would have a basis avoiding these twins and the harmony would give a basis containing the twins; this is a contradiction. So, all vectors except this pair of twins is a harmonic subset of $U$. |
Aug 30 |
answered | Embedding of a “quotient graph” |
Aug 28 |
awarded | Nice Question |
Aug 28 |
comment |
Basis removal gives a basis
@Gjergji: honestly, there are no research-level motivations. It was intended to be a problem for students (with the integer 10 probably) but --- I discovered that my question seems to be not so easy (for me). So, if there is a simple solution for 10, I shall be glad. |
Aug 28 |
comment |
Basis removal gives a basis
@Gerry, it does not matter whether we are speaking about bases of $X$ (= bases of $\langle X\rangle$) or about bases of the whole space $V$. The answers will be obviously the same. |
Aug 28 |
comment |
Basis removal gives a basis
@Gerry, A basis of a set of vectors is its maximal linearly independent subset. So, Joël and Tom are right. Thank you, Tom. |
Aug 27 |
asked | Basis removal gives a basis |
Aug 25 |
revised |
Is there a better description of this class of discrete groups?
added 100 characters in body |
Aug 25 |
comment |
Is there a better description of this class of discrete groups?
Almost. I replaced "set" with "class" in the deTeXified sentence. |
Aug 25 |
revised |
Is there a better description of this class of discrete groups?
added 38 characters in body |
Aug 25 |
answered | Is there a better description of this class of discrete groups? |
Aug 23 |
comment |
On “super connected” graphs
"we can take any of these, say $H_1$, and $H_1 \cup \{a, b\}$ will be connected..." As far as I understand, we should take a component $H_1$ such that $H_1 \cup \{a, b\}$ is connected. It is not automatically. |
Aug 8 |
comment |
Abelian subgroups of maximum order in $p$-Groups
I do not understand $\frac{p+3}{2}$. The index should be a power of $p$, right? |
Aug 8 |
comment |
Abelian subgroups of maximum order in $p$-Groups
@Dietrich, no, it is not. |