bio | website | halgebra.math.msu.su/staff/… |
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location | Moscow | |
age | ||
visits | member for | 3 years, 1 month |
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Nov 27 |
comment |
Powers of finite simple groups
Oh, I see: mathoverflow.net/a/53162/24165 |
Nov 23 |
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Powers of finite simple groups
The automorphism groups of finite simple groups are well known. So, we have to calculate the (non-reduced) Euler function $\phi_n(G)$ (ie. the number of generating n-tuples). In Section 1.1, Collins describes a technique of such calculations that allowed Hall (in 1936) to calculate, e.g., $\phi_2(A_5)=19\cdot 120$ (ie. $h_2(A_5)=19$). |
Nov 23 |
awarded | Custodian |
Nov 23 |
reviewed | Approve MMSE estimator expressed through cumulants |
Nov 22 |
revised |
Is the Amitsur-Levitzki identity essentially unique?
an arXiv tag added |
Nov 22 |
suggested | approved edit on Is the Amitsur-Levitzki identity essentially unique? |
Nov 22 |
awarded | Nice Answer |
Nov 22 |
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bounding from below the cardinality of a set of generators of the $n$-fold cartesian product group of a finite group
See (my answer to) a similar question: mathoverflow.net/q/187736/24165 . |
Nov 22 |
revised |
Powers of finite simple groups
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Nov 22 |
revised |
Is the Amitsur-Levitzki identity essentially unique?
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Nov 22 |
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Is the Amitsur-Levitzki identity essentially unique?
... and why "combinatorics"? |
Nov 22 |
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Is the Amitsur-Levitzki identity essentially unique?
Why this is tagged "commutative algebra"? |
Nov 22 |
revised |
Is the Amitsur-Levitzki identity essentially unique?
added 1 character in body |
Nov 22 |
answered | Is the Amitsur-Levitzki identity essentially unique? |
Nov 22 |
revised |
Powers of finite simple groups
added 1 character in body |
Nov 22 |
answered | Powers of finite simple groups |
Nov 20 |
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Normal Covering of a Finite Group
This Corollary 5.5 follows immediately from the theorem of Brodie, Chamberlain and Kapp, PAMS 1988, see Nick Gill's answer: mathoverflow.net/a/185604/24165 . |
Nov 9 |
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Is the equational theory of commutative vN regular rings decidable?
Thomas, every finitely generated associative commutative ring is residually finite. (For free rings (= polynomial rings), this is almost obvious.) |
Nov 9 |
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Possible cardinality and weight of an ordered field
Taras, you may write an answer and accept your own answer to make the question "closed". |
Nov 9 |
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Explicitly showing that a free group is LERF
Surely, there is an algorithm for finding this finite-index subgroup and the free complement in this subgroup. Just look at the proof of Hall's free-factor theorem. It is quite easy using Stallings graphs.. |